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3 years ago

Can someone help me with my science please

Physics

1 answer:

Natali5045456 [20]3 years ago

4 0

Explanation:

what is the question please

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Compute the expected shell-model quadrupole moment of 209Bi () and compare with the experimental value, - 0.37 b

Over [174]

Answer:

0.22 b

Explanation:

Quadrupole moment of the nucleon is,

$Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2}$

And also,

$R^{2}=R^{2} _{0}A^{\frac{2}{3} }$

And, $R _{0}=1.2\times 10^{-15}m$

Now,

$Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2} _{0}A^{\frac{2}{3} }$

For Bismuth $j=\frac{9}{2}$ and A is 209.

$Q=-\frac{2\frac{9}{2} -1}{2(\frac{9}{2} +1)}\frac{3}{5}(1.2\times 10^{-15}) ^{2}(209)^{\frac{2}{3} }\\Q=0.628\times 35.28\times 10^{-30} \\Q=22.15\times 10^{-30} m^{2} \\Q=0.2215\times 10^{-28} m^{2} \\Q=0.22 barn$

Therefore, the expected value of quadrupole is 0.22 b which is quite related with experimental value which is 0.37 b

3 0

3 years ago

A cylindrical piece of aluminum is 6.00cm y’all and 2.00cm in radius how much does it weigh

Harlamova29_29 [7]

Answer:

2.00 N

Explanation:

Weight is mass times gravity:

W = mg

Mass is density times volume:

m = ρV

Volume of a cylinder is:

V = πr²h

Finding the volume:

V = π (2.00 cm)² (6.00 cm)

V = 75.4 cm³

The density of aluminum is 2.7 g/cm³. Finding the mass:

m = (2.7 g/cm³) (75.4 cm³)

m = 204 g

Finding the weight:

W = (0.204 kg) (9.8 m/s²)

W = 2.00 N

The aluminum cylinder weighs 2.00 N.

3 0

3 years ago

When Earth pulls on an object, that object also pulls on Earth. The values of these two forces are . This phenomenon can be expl

algol13

The values of these two forces are equal. Your weight on Earth is equal to the Earth's weight on you. When you and the Earth fall toward each other, your acceleration is greater than the Earth's acceleration, because your mass is less than the Earth's mass.

5 0

4 years ago

Read 2 more answers

A solenoid that is 133 cm long has a radius of 2.99 cm and a winding of 1740 turns; it carries a current of 3.91 A. Calculate th

erica [24]

Answer:

The value is $B = 0.0643 \ T$