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Alenkinab [10]
3 years ago
14

A gym has yoga classes. Each class has 14 students. If there are c classes, write an equation to represent the total number of s

tudents s taking yoga.
Mathematics
2 answers:
icang [17]3 years ago
6 0

Answer:

14c

Step-by-step explanation:

There are c classes of yoga.

Each class has 14 students.

So the total number of students taking yoga = 14 multiplied by c

Therefore the equation to represent the total number of students taking yoga = 14c

MA_775_DIABLO [31]3 years ago
3 0
1 class = 14

c classes = 14c

Answer: s = 14c
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He rain caused the river to ride a total of 6 2/3 inches. The river was rising at an average of 2/3 of an inch each hour. How ma
Kobotan [32]
To find out how many hours it rained, divide the total rise in the river by the amount it rose every hour.

\sf 6\dfrac{2}{3}\div\dfrac{2}{3}

First convert the mixed number into an improper fraction. We do this by multiplying the denominator to the whole number, adding it to the numerator, which becomes our new numerator, and we keep the denominator the same:

\sf\dfrac{20}{3}\div\dfrac{2}{3}

When dividing fractions we flip(the reciprocal) the one we're dividing by and multiply:

\sf\dfrac{20}{3}\times\dfrac{3}{2}

Multiply the numerators and denominators together:

\sf\dfrac{60}{6}

Simplify by dividing:

\boxed{\sf 10}

So it rained for 10 hours.
5 0
3 years ago
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
3 years ago
Simplify (2/9)^3<br> A.6/9<br> B.8/729<br> C.2/720
saw5 [17]

<u>Answer:</u>

\frac{8}{729}


<u>Explanation:</u>

Before we begin, remember that:

(\frac{a}{b})ⁿ = \frac{a^n}{b^n}


This means that power is distributed in case of division


The given is:

(\frac{2}{9} )^3


Applying the above rule, we would get:

(\frac{2}{9} )^3 = \frac{2^3}{9^3} = \frac{2*2*2}{9*9*9} = \frac{8}{729}


Hope this helps :)


8 0
3 years ago
I’ll give brainliest to first answer
Kay [80]

Answer:

f^-1 (9) = 7 equals f = 9/7

Step-by-step explanation:

f^-1 x 9 = 7, f ≠ 0

1/f x 9 = 7

9/f = 7

9 = 7f

7f = 9

8 0
3 years ago
Which of the following illustrates the truth value of the given conditional statement?
lions [1.4K]

Answer:

6x3

Step-by-step explanation:

sorry if wrong

5 0
4 years ago
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