The electric force between two charge objects is calculated through the Coulomb's law.
F = kq₁q₂/d²
The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given,
2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d²
The value of d is equal to 0.10 m.
Answer:
a) θ = 14.23º, b) θ₂ = 75.77, c) t = 0.6019 s
Explanation:
This is a missile throwing exercise.
a) the reach of the ball is the distance traveled for the same departure height
R =
sin 2θ =
sin 2θ = 7.00 9.8 / 12.0²
2θ = sin⁻¹ (0.476389) = 28.45º
θ = 14.23º
the complementary angle that gives the same range is the angle after 45 that the same value is missing to reach 90º
θ ’= 90 -14.23
θ’= 75.77º
b) the two angles that give the same range are
θ₁ = 14.23
θ₂ = 75.77
the greater angle has a much greater height so the time of the movement is greater and has a greater chance of being intercepted by the other team.
C) the time of the pass can be calculated with the expression
x = v₀ₓ t
t = x / v₀ₓ
t = 7 / 11.63
t = 0.6019 s
Bernini's sculpture "Apollo and Daphne" implies a chase scene motion. Apollo and Daphne<span> is a life-sized Baroque marble </span>sculpture<span> by Italian artist Gian Lorenzo </span>Bernini<span>, executed between 1622 and 1625. Hope this answers the question. Have a nice day.</span>
Answer:
The electromotive force is <u>the maximum potential difference between the terminals of a battery.</u>
Answer:
5.59 m/s
Explanation:
We are given;
Mass = 110 kg
Initial velocity: u = 13.41 m/s
Force = 615 N
Time(t) = 1 s
Now, formula for force is;
Force = mass x acceleration
Thus;
615 = 110 × acceleration
Acceleration(a) = 615/110 = 5.591 m/s²
Now, using Newton's first law of motion, we can find acceleration (a). Thus;
v = u + at
v = 13.41 + (5.591 × 1)
v ≈ 19 m/s
So, change in velocity is;
Final velocity(v) - Initial velocity(u) = 19 - 13.41 = 5.59 m/s