Answer:
Explanation:
moment of inertia of reel = 1/2 mr² , m is mass and r is radius of the reel
= .5 x .7 x .0524²
= 96.1 x 10⁻⁵
If force required be F
F x .0524 - 1.88 is net torque acting on the reel
F x .0524 - 1.88 = moment of inertia x angular acceleration.
F x .0524 - 1.88 = 96.1 x 10⁻⁵ x 65.7
F x .0524 - 1.88 = .063
F x .0524 = .063 + 1.88
F = 37.08 N
Ness awaits you sir, please be theoretical and positive eeeeeeeee
Weight=mass x gravitational force
W=60 x 1/100 x 10
W=60 x 0.1
W=6N
Answer:
X=92.49 m
Explanation:
Given that
u= 21 m/s
h= 97 m
Time taken to cover vertical distance h
h= 1/2 g t²
By putting the values
97 = 1/2 x 10 x t² ( g = 10 m/s²)
t= 4.4 s
The horizontal distance
X= u .t
X= 21 x 4.4
X=92.49 m
Answer:
e. 2ωs / √5
Explanation:
The rotational kinetic energy of any rigid body, like an extension of the translational kinetic energy, is defined as follows:
Krot = 1/2 *I * ω²
For a solid sphere of mass M and radius R, the moment of inertia regarding any axis through its center, is as follows:
I =2/5 M*R²⇒ Krot(sp) = 1/2 (2/5 M*R²)*ωs² (1)
For a solid cylinder, rotating through an axis running through the central axis of the cylinder, the moment of inertia can be calculated as follows:
I = 1/2 M*R² ⇒ Krot(c) = 1/2 (1/2*M*R²)*ωc² (2)
As both rotational kinetic energies must be equal each other, we can equate (1) and (2), as follows:
1/2 (2/5 M*R²)*ωs² = 1/2 (1/2*M*R²)*ωc²
Simplifying common terms, and solving for ωc, we have:
ωc = 2*ωs /√5
