Answer:
See below.
Step-by-step explanation:
Ethers react with HI at high temperature to produce an alky halide and an alcohol.
R-OR' + HI ⟶ R-I + H-OR'
<em>Benzylic ethers</em> react by an Sₙ1 mechanism by forming the stable benzyl cation.
- PhCH₂-OR + HI ⟶ PhCH₂-O⁺(H)R + I⁻ Protonation of the ether
- PhCH₂-O⁺(H)R ⟶ PhCH₂⁺ + HOR Sₙ1 ionization of oxonium ion
- PhCH₂⁺ + I⁻ ⟶ PhCH₂-I Nucleophilic attack by I⁻
If there is excess HI, the alcohol formed in Step 2 is also converted to an alkyl iodide:
ROH +HI ⟶ R-I + H-OH
Thus, benzyl ethyl ether reacts to form benzyl iodide (a) and ethanol (b).
The ethanol reacts with excess HI in an Sₙ2 reaction to form ethyl iodide (c).
Answer:
Explanation:The Î""G°′ of the reaction is −7.180 kJ·mol−1. Calculate the equilibrium constant for the reaction at 25 °
I would say is b. The answer
<span>Deinonychus due to its backwards teeth</span>
Answer:
35 mL
Explanation:
Let the amount of 75% mixture needed be A.
The amount of each solution with their respective concentration to be added together can be expressed as:
0.75A + 0.3(280)...............eqn 1
The addition of the two solution must merge with the expected concentration and this can be expressed as:
0.35(A + 280).............eqn 2
Eqn 1 must be equal to eqn 2, hence:
0.75A + 0.3(280) = 0.35(A + 280)
Solve for A.
0.75A + 84 = 0.35A + 98
0.40A = 14
A = 35
Hence, 35 mL of the 75% mixture will be needed.
