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Artemon [7]
3 years ago
10

The Î""G°′ of the reaction is −7.180 kJ·mol−1. Calculate the equilibrium constant for the reaction at 25 °C.

Chemistry
1 answer:
nasty-shy [4]3 years ago
5 0

Answer:

Explanation:The Î""G°′ of the reaction is −7.180 kJ·mol−1. Calculate the equilibrium constant for the reaction at 25 °

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A flask contains an equal mixture of oxygen and argon. Which of the following statements is true about the effusion of the gases
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Given that the pressure, temperature and area of effusion is constant, the rate of effusion is inversely proportional to the square root of the molecular mass of the gas.
Mr Oxygen = 32
Mr Argon = 40
Effusion Oxygen = 1/√32
Effusion Argon = 1/√40
Effusion Oxygen / Effusion Argon = √(40) / √(32)
=√(40/32) = √(5/4) = 1.19
Thus, Oxygen will effuse 1.19 times faster than Argon. The second option is correct.
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4 years ago
A shiny piece of metal has a volume of 315 cm3 and a mass of 851 g. what is the density of the metal?
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8 0
1 year ago
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In nuclear reactions, which of the following is likely to occur?
777dan777 [17]
It is both a and b
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4 0
3 years ago
Electrons will readily tunnel out of the surface of a metal when a sufficiently high electric field E is applied to the surface.
puteri [66]

Answer:

1 that is 100%

Explanation:

here it is given that Fermi energy of the of the metal = 5 e.V

work function= 4 e.V

we have to find the probability that an incident electron will tunnel out if E=109 V/m

WORK FUNCTION : work function is defined as the energy required to withdraw an electron completely from the metal surface.

now the energy per unit volume in electric field is given by

E= \frac{1}{2}\times \varepsilon_0\times E^{2}

E=\frac{1}{2}\times 8.854\times 10^{-12}\times \left ( 10^{9} \right )^2

E=4.427\times 10^{6}joule

in electron volt E=4.427\times 10^{6}joule × 6.24\times 10^{18}

E=2.76\times 10^{25}e.V

hence the applied energy per unit volume is greater than the work work function of electron so there is probability of 100% that electron will tunnel out

3 0
3 years ago
Si (IV) + CL2 --> SICLY O synthesis O decomposition O single displacement O double displacement O MgCl2 + NaOH --> Mg(OH)2
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Answer:

1. decomposition

2. double displacement

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