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Artemon [7]
3 years ago
10

The Î""G°′ of the reaction is −7.180 kJ·mol−1. Calculate the equilibrium constant for the reaction at 25 °C.

Chemistry
1 answer:
nasty-shy [4]3 years ago
5 0

Answer:

Explanation:The Î""G°′ of the reaction is −7.180 kJ·mol−1. Calculate the equilibrium constant for the reaction at 25 °

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Draw all resonance structures for the nitryl fluoride molecule, no2f.
denis-greek [22]
From  electronic  configuration valence electron of  Nitrogen is 5,  oxygen  6x2  which 12 since it  involve  two  molecules ,  that of is frulorine is  7, and  that No2F is 24  which  is  gotten  form  adding (5,12,7  ).All  resonance structure  are  as  follows
       F
 ..    I    ..
: O : N :O: 
 
              ..
     OR  : F:
              I                             

             N                                                  ..                                                                                                                                    : F:

          /         \                        or                   I

   ..                 ..                                               N

:O  :            :O:                                       / /        \\
                                                            / /               \\
                                                         :O :            :  O:
7 0
4 years ago
Determine the final temperature of sample with a specific heat of 1.1 J/g°C and a mass of 385 g if it starts out at a temperatur
Assoli18 [71]

Answer:

T2 =21.52°C

Explanation:

Given data:

Specific heat capacity of sample = 1.1 J/g.°C

Mass of sample = 385 g

Initial temperature = 19.5°C

Heat absorbed = 885 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )

885 J = 423.5 J/°C× (T2 - 19.5°C )

885 J / 423.5 J/°C = (T2 - 19.5°C )

2.02°C = (T2 - 19.5°C )

T2 = 2.02°C + 19.5°C

T2 =21.52°C

8 0
3 years ago
What is the ph of a saturated solution of aluminum hydroxide?
sasho [114]
Answer is attached  below ( sorry for mistake )

6 0
3 years ago
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3 years ago
Below are shown, for five metals, reduction reactions and standard electrode potential values. which of these metals is the leas
just olya [345]
Above question is incomplete. Complete question is attached below
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.

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On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive. 


7 0
4 years ago
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