Question

You need a 35% alcohol solution. On hand, you have a 280 mL of a 30% alcohol mixture. You also have 75% alcohol mixture. How much of the 75% mixture will you need to add to obtain the desired solution

Answer 1

Answer:

35 mL

Explanation:

Let the amount of 75% mixture needed be A.

The amount of each solution with their respective concentration to be added together can be expressed as:

0.75A + 0.3(280)...............eqn 1

The addition of the two solution must merge with the expected concentration and this can be expressed as:

0.35(A + 280).............eqn 2

Eqn 1 must be equal to eqn 2, hence:

0.75A + 0.3(280) = 0.35(A + 280)

Solve for A.

0.75A + 84 = 0.35A + 98

0.40A = 14

A = 35

Hence, 35 mL of the 75% mixture will be needed.