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Nonamiya [84]
3 years ago
13

A wheel is rotating about an axis that is in the

Physics
1 answer:
Schach [20]3 years ago
4 0

Answer:

A) \alpha=+0.625rad/s^2 is Positive

B) t2 = 6.4s

C) t1 = 9.6s

D) \Delta \theta =-16rad

Explanation:

Let's first calculate the aangular acceleration:

\alpha=\frac{\omega f-\omega o}{\Delta t} = +0.625rad/s^2

So, acceleration is positive

Let Δt be divided into 2 time intervals t1 and t2 where t1 is the interval when the wheel goes from -6.00 rad/s to 0.00 rad/s

t1 = \frac{\omega 1 - \omega o}{\alpha}=\frac{0rad/s - (-6rad/s)}{0.625rad/s^2}

t1 = 9.6s   This is the interval where speed is decreasing

The other time interval t2 will be:

t2 = 16s - t1 = 6.4s  This is the interval where speed is increasing

The angular displacement is:

\Delta \theta=\omega o *\Delta t+\alpha*\Delta t^2/2

\Delta \theta =-16rad

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