Answer: E/4 ( one - fourth of it electric field)
Explanation:
The electric field of a point charge is given below as
E =kq/r²
E = electric field,
K = electric constant
q = magnitude of electric charge
r = distance between point charge and electric field.
It can be seen that only E and r are the only variable here and also, E is inversely proportional to r²
Which implies that
E = k/r² , k = E × r²
E1 ×(r1)² = E2 × (r2)²
Let E1 = E, r1 =1, r2 = 2 and E2 =?
Let us substitute the parameters
E × 1 = E2 × 2²
E × 1 = E2 × 4
E = E2 × 4
E2 = E/4
Which implies that the electric field at the second distance (r =4) is one fourth of the initial electric field.
Explanation:
Given Data
Total mass=93.5 kg
Rock mass=0.310 kg
Initially wagon speed=0.540 m/s
rock speed=16.5 m/s
To Find
The speed of the wagon
Solution
As the wagon rolls, momentum is given as
P=mv
where
m is mass
v is speed
put the values
P=93.5kg × 0.540 m/s
P =50.49 kg×m/s
Now we have to find the momentum of rock
momentum of rock = mv
momentum of rock = (0.310kg)×(16.5 m/s)
momentum of rock =5.115 kg×m/s
From the conservation of momentum we can find the wagons momentum So
wagon momentum=50.49 -5.115 = 45.375 kg×m/s
Speed of wagon = wagon momentum/(total mass-rock mass)
Speed of wagon=45.375/(93.5-0.310)
Speed of wagon= 0.487 m/s
Throwing rock backward,
momentum of wagon = 50.49+5.115 = 55.605 kg×m/s
Speed of wagon = wagon momentum/(total mass-rock mass)
speed of wagon = 55.605 kg×m/s/(93.5kg-0.310kg)
speed of wagon= 0.5967 m/s
I think the correct answer is A mark has greater gravitational potential energy
:)
Volume = mass / density = 45.6/10.5 = .... L