Answer:
t = 4 seconds
Explanation:
The question is "The intensity of current flowing through a conductor is 2μA. How long will it take 5x1013 electrons to cross a certain cross section of the conductor?
"
Current, 
No of electrons, 
We need to find how long will it take to given no of electrons to cross a certain cross section of the conductor.
Electric current,

t is time
Also, q = ne

So, it will take 4 seconds.
Answer:
The person on Earth will have to exert more force to lift their block
Explanation:
The mass of the blocks to be lifted = 200 kg
The location of the first person = On Earth
The location of the second person = On the Moon
The force a person will have to exert to lift the block = The weight of the block = The gravitational force, F, on the block which is given as follows;

Where;
= The acceleration due to gravity on the Earth or the Moon, depending on the location of the block
m₂ = The mass of the block
Therefore, given that the acceleration due to gravity on the Earth is larger than the acceleration due to gravity on the Moon, the weight of the block on the Earth is larger than the weight of the block on the Moon, and the person on Earth have to exert more force to lift the heavier weight of the block on Earth than the person on the Moon will have to exert to lift the same block as the block has a lower weight on the Moon due to lower acceleration due to gravity on the Moon.
Answer:
Explanation:
To calculate an effect size, called Cohen's d , for the one-sample t-test you need to divide the mean difference by the standard deviation of the difference, as shown below. Note that, here: sd(x-mu) = sd(x) . μ is the theoretical mean against which the mean of our sample is compared (default value is mu = 0).
Acceleration is the rate of
change of the velocity of an object that is moving. This value is a result of
all the forces that is acting on an object which is described by Newton's
second law of motion. <span>Calculation of such is
straightforward, if we are given the final velocity, the initial velocity and
the total time interval. We can just use the kinematic equations. Fortunately, we are given these values. So, we calculate as follows:
</span>
acceleration = v - v0 / t
acceleration = (80 mph - 50 mph) ( 1 h / 3600) / 5 s
acceleration = 1.67 x 10^-3 m / s^2
Therefore, the acceleration of the car is 1.67 x 10^-3 m / s.
Answer: The mass would be 1000m3 and the volume would be 1000kg
Explanation: