Question

A plate has an area of 1m square. It slide down an incline plane , having an angle of inclined 60° to horizontal, which a velocity of 0.75m/s. The thickness of oil film between the plate and the plate is 2mm. Find the viscosity of the fluid if the weight of the plate is 90N

Answer 1

Answer:

$\mu =0.169704 Ns/m^2$

Explanation:

From the question we are told that

Area of plate$a=1m^2$

Angle of inclination $\theta=60 \textdegree$

Velocity $v=0.75m/s$

Thickness of oil $t=2mm$

Weight of plate $w=90N$

Generally the equation for shear force is mathematically given by

$F=mgsin45 \textdegree$

$F=90sin45 \textdegree$

$F=63.639N$

$F=\mu* \frac{v}{t}$

$F=\mu* \frac{0.75}{2*10^-^3}$

$\mu* \frac{0.75}{2*10^-^3}=63.639N$

$\mu =\frac{63.639}{375}$

Therefore viscosity is given by

$\mu =0.169704 Ns/m^2$