Question

A high power line carries a current of 1.0 kA. What is the strength of the magnetic field this line produces at the ground, 10 m away? ( μ 0 = 4π × 10 -7 T ∙ m/A)

Answer 1

Answer:

The strength of the magnetic field that the line produces is $2x10^{-5} Tesla$.

Explanation:

From Biot-Savart law, the equation to determine the strength of the magnetic field for any straight wire can be deduced:

           

$B = \frac{\mu_{0}I}{2\pi r}$ (1)      

                                     

Where $\mu_{0}$ is the permiability constant, I is the current and r is the distance from the wire.    

             

Notice that it is necessary to express the current, I, from kiloampere to ampere.

$I = 1.0kA \cdot \frac{1000A}{1kA}$ ⇒ $1000A$

Finally, equation 1 can be used:

$B = \frac{(4\pi x10^{-7}T.m/A)(1000A)}{2\pi (10m)}$    

           

$B = 2x10^{-5}T$    

Hence, the strength of the magnetic field that the line produces is $2x10^{-5} Tesla$.