Answer:
525 Bq
Explanation:
The decay rate is directly proportional to the amount of radioisotope, so we can use the half-life equation:
A = A₀ (½)^(t / T)
A is the final amount
A₀ is the initial amount,
t is the time,
T is the half life
A = (8400 Bq) (½)^(18.0 min / 4.50 min)
A = (8400 Bq) (½)^4
A = (8400 Bq) (1/16)
A = 525 Bq
Answer:
8.27°
Explanation:
To angle difference will be determined by the difference in the displacement of the springs, produced by the weight of the center of mass of the rod.
![d=y_1-y_2=\frac{F_1}{k_1}-\frac{F_2}{k_2}=\frac{0.5mg}{31N/m}-\frac{0.5mg}{63N/m}\\\\d=0.5(1.6kg)(9.8m/s^2)[\frac{1}{31N/m}-\frac{1}{63N/m}]=0.128m](https://tex.z-dn.net/?f=d%3Dy_1-y_2%3D%5Cfrac%7BF_1%7D%7Bk_1%7D-%5Cfrac%7BF_2%7D%7Bk_2%7D%3D%5Cfrac%7B0.5mg%7D%7B31N%2Fm%7D-%5Cfrac%7B0.5mg%7D%7B63N%2Fm%7D%5C%5C%5C%5Cd%3D0.5%281.6kg%29%289.8m%2Fs%5E2%29%5B%5Cfrac%7B1%7D%7B31N%2Fm%7D-%5Cfrac%7B1%7D%7B63N%2Fm%7D%5D%3D0.128m)
by a simple trigonometric relation you obtain that the angle:

hence, the angle between the rod and the horizontal is 8.27°
Answer: the magnetic wave will travel out of the screen.
Explanation:
Electric field direction is perpendicular to the magnetic field direction. Both are also perpendicular to the direction of the particles.
Using right hand rule to solve this problem,
This pointed finger depicts the electric field direction which the curly fingers depict the direction of the magnetic field. The pointed thumb will depict the direction in which the wave travel. Which is out of the screen.
Answer:
I = 3.9 x 10⁷ W/m²
Explanation:
given,
Sheet of black paper dimension = 8.5 x 11 inch
Area of sheet = 8.5 x 11 = 93.5 inch^2
1 inch =0.0254 m
Area = 0.06032 m²
mass of sheet = 0.80 g
Force = m g = 0.8 x 9.8 x 10⁻³ N
= 7.84 x 10⁻³ N
speed of light = c = 3 x 10⁸ m/s
Using equation

where I is the intensity of light



I = 3.9 x 10⁷ W/m²
Intensity of the light is equal to I = 3.9 x 10⁷ W/m²
3 Solar System
The Milky Way
The Galaxy
IDK