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gtnhenbr [62]
3 years ago
10

A balloonist drops his camera from a height of 100 m while his balloon is ascending at 5 m/s. How

Physics
1 answer:
ExtremeBDS [4]3 years ago
6 0
20 i think is the answer
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The surface charge density on an infinite charged plane is - 2.10 ×10−6C/m2. A proton is shot straight away from the plane at 2.
inn [45]

Explanation:

Formula to calculate electric field because of the plate is as follows.

         E = \frac{\sigma}{2 \times \epsilon_{o}}

            = \frac{2.10 \times 10^{-6}}{2 \times 8.85 \times 10^{-12}}

           = 1.18 \times 10^{5} N/C

Now, we will consider that equilibrium of forces are present there. So,

                   ma = qE

       a = \frac{1.6 \times 10^{-19} \times 1.18 \times 10^{5}}{1.67 \times 10^{-27}}

          = 1.13 \times 10^{13} m/s^2

According to the third equation of motion,

         v^{2} = 2 \times a \times d

or,      d = \frac{v^{2}}{2d}

             = \frac{(2.4 \times 10^{6})^{2}}{2 \times 1.13 \times 10^{13}}

             = 0.254 m

Thus, we can conclude that the proton will travel 0.254 m before reaching its turning point.

7 0
3 years ago
Why the center of Newton rings is dark?​
RideAnS [48]
The point of contact the path difference is zero but one of the interfering ray is reflected so the effective path difference becomes λ/2 thus the condition of minimum intensity is created in the center.
3 0
4 years ago
Read 2 more answers
How does hitting a ball with a tennis racquet involve action and reaction forces?
iragen [17]

Answer:

In a tennis match, the racket exerts the action force on the ball and, as the ball hits it, it exerts an equal and opposite reaction force on the racket. The rocket launches because it pushes on the gas coming out the back end for the action force, while the gas pushes the rocket upward with a reaction force.

5 0
4 years ago
An open pipe, 0.29 m long, vibrates in the second overtone with a frequency of 1,227 Hz. In this situation, the fundamental freq
Andru [333]

Answer:

f = 409 Hz

Explanation:

We have,

Length of the open organ pipe, l = 0.29 m

Frequency of vibration of second overtone, f_2 = 1227 Hz

It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :

f_2=\dfrac{3v}{2l}

v is speed of sound

Let f is the fundamental frequency. It is given by :

f=\dfrac{v}{2l}

The relation between f and f₂ can be written as :

f_2=3f\\\\f=\dfrac{f_2}{3}\\\\f=\dfrac{1227}{3}\\\\f=409\ Hz

So, the fundamental frequency of the pipe is 409 Hz.              

6 0
3 years ago
Nuclear waste disposal is one of the largest issues with nuclear power. Cesium-137 is one of the high level waste products in an
vodomira [7]

Answer:

A sample of 5.2 mg  decays to .65 mg or to 1/8 of its original amount.

1/8 = 1/2 * 1/2 * 1/2 or 3 half-lives.

3 * 30.07 = 90 yrs for 5.2 mg to decay to .65 mg

You can get these other numbers similarly:

5.2 / .0102 = 510  requires about 9  half-lives which is 30 * 9 = 270 yrs

7 0
3 years ago
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