Answer:
w = 4,786 rad / s
, f = 0.76176 Hz
Explanation:
For this problem let's use the concept of angular momentum
L = I w
The system is formed by the two discs, during the impact the system remains isolated, we have the forces are internal, this implies that the external torque is zero and the angular momentum is conserved
Initial Before sticking
L₀ = 0 + I₂ w₂
Final after coupling
= (I₁ + I₂) w
The moments of inertia of a disk with an axis of rotation in its center are
I = ½ M R²
How the moment is preserved
L₀ = 
I₂ w₂ = (I₁ + I₂) w
w = w₂ I₂ / (I₁ + I₂)
Let's reduce the units to the SI System
d₁ = 60 cm = 0.60 m
d₂ = 40 cm = 0.40 m
f₂ = 200 min-1 (1 min / 60 s) = 3.33 Hz
Angular velocity and frequency are related.
w₂ = 2 π f₂
w₂ = 2π 3.33
w₂ = 20.94 rad / s
Let's replace
w = w₂ (½ M₂ R₂²) / (½ M₁ R₁² + ½ M₂ R₂²)
w = w₂ M₂ R₂² / (M₁ R₁² + M₂ R₂²)
Let's calculate
w = 20.94 8 0.40² / (12 0.60² + 8 0.40²)
w = 20.94 1.28 / 5.6
w = 4,786 rad / s
Angular velocity and frequency are related.
w = 2π f
f = w / 2π
f = 4.786 / 2π
f = 0.76176 Hz
Answer:
flattened by pressure; squeezed or pressed together.
Explanation:
Answer:
Correct answer: Fg = m · g
Explanation:
Newton's second law states that if a resultant force is applied to an object, the object begins to move at an accelerated rate.
The formula that presents this is:
F = m · a
this formula applies to an object moving on some surface
where m is the mass of the object and a the acceleration of the object
Let's take it now and watch the free fall:
The formula that presents this is:
Fg = m · g
this formula applies to an object moving at free fall in vertical direction
Free fall is also an accelerated movement to which Newton's second law applies.
where m is the mass of the object and g the gravitation acceleration of the object . We also know that g is equal:
g = γ · Me / d² where Me is mass of the earth
God is with you!!!