3KI + HClO + HCl = 2KCl + K[I₃] + H₂O
10FeSO₄ + 2KMnO₄ + 8H₂SO₄ = 5Fe₂(SO₄)₃ + 2MnSO₄ + K₂SO₄ + 8H₂O
Answer:
For the first ionization energy for an N2 molecule, the molecular orbital that the electron is removed from is the p orbital.
It should be noted that valence electrons simply refer to the electrons in an atom that holds the last orbital that is required for chemical bonding with other elements.
The existence of valence electrons can define the chemical properties of that atom. For the first energy in ionization of an N2 molecule, the molecular orbital where the electron could be extracted is the p orbital since it has the highest energy level.
The 3% mass/volume H₂O₂ means 3 g of H₂O₂ in 100 ml of water.
Now, Molarity (M) = No. of moles of H₂O₂ / Volume of solution in liter
No. of moles of H₂O₂ = Mass / Molar mass = 3 g / 34 g/mol = 0.088 mol
So, molarity = 0.088 × 1000 ml / 100 ml = 0.88 M
In case of 2.25 % H₂O₂,
No of moles = 2.25 g / 34 g/mol = 0.066 mol
Molarity = 0.066 mol / 0.100 L = 0.66 M.