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3 years ago

What’s the answer for -|2x-8|-6=-12

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

6 0

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

Answer:

x=7,1

Hope this helps, if not then I'm sorry

Have a nice day!

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What inequality symbol does "at least" correspond to?

Sever21 [200]

Answer:

C, if someone else gets the same answer as me then its right

Step-by-step explanation:

8 0

3 years ago

Twenty-five samples of 100 items each were inspected when a process was considered to be operating satisfactorily. In the 25 sam

notsponge [240]

a) The estimate of the proportion of defectives when the process is in control is 0.054

b) The standard error of the proportion if the sample size is 100 is 0.0226.

c) The upper control limit is 0.1218 and the lower control limit is 0 (since LCL < 0 and p > 0, we can write LCL = 0).

<h3>What are the formulas for finding the estimate of the proportion, standard variation, and control limits?</h3>

1) The estimate of the proportion of success is

p = (number of success)/(total number of samples)

I.e., p = x/N

2) The standard deviation of the proportion of success is

$\sigma_p = \sqrt{\frac{p(1-p)}{n} }$

3) The upper and lower control limits for a control chart are:

L.C.L = p - 3 $\sigma_p$

and U.C.L = p + 3 $\sigma_p$

<h3>Calculation:</h3>

It is given that, there are 25 samples of 100 items each.

So, the total number of items i.e., the total sample size,

N = 25 × 100 = 2500

In 25 samples, a total of 135 items were found to be defective.

So, the number of defectives x = 135

a) The estimate of the proportion of defectives is p = x/N

On substituting, we get

p = 135/2500 = 0.054

b) The standard error of the proportion if the sample of size 100 is calculated by

$\sigma_p = \sqrt{\frac{p(1-p)}{n} }$

On substituting p = 0.054 and n = 100, we get

$\sigma_p = \sqrt{\frac{0.054(1-0.54)}{100} }$

= 0.0226

c) The control limits for the control chart are:

Upper control limit = p + 3 $\sigma_p$

⇒ U.C.L = 0.054 + 3(0.0226) = 0.054 + 0.0678 = 0.1218

Lower control limit = p - 3 $\sigma_p$

⇒ L.C.L = 0.054 - 3(0.0226) = 0.054 - 0.0678 = - 0.0138 ≈ 0

(Since we know that the lower control limit should not be a negative value, it is made equal to 0).

Learn more about an estimate of the proportion here:

brainly.com/question/23986522

#SPJ4

7 0

1 year ago

Pls help i give you brainliest

stepladder [879]

Kimi no toriko ni natte ti shi mae ba kitto

7 0

3 years ago

Solve the system of equations. 3x+4y=−23 x=3y+1

larisa86 [58]

Answer:

Step-by-step explanation:

3x+4y=−23.........(1)

x=3y+1 .........(2)

Putting (2) in (1)

3(3y + 1) + 4y = -23

9y + 3 + 4y = -23

9y + 4y = -23 - 3

13y = -26

y = -26/13

y = -2

Putting y into (2)

x=3y+1

x = 3(-2) + 1

x = -6 + 1

x = -5

7 0

3 years ago

HELP!!!!

ch4aika [34]

Answer:

$8 y^{50}$

Step-by-step explanation:

Given (64 y Superscript 100 Baseline) Superscript one-half.

Let us write it into an equation.

$\left(64 y^{100}\right)^{\frac{1}{2}}$

Apply radical rule: $\sqrt[n]{a}=a^{\frac{1}{2}}$ and $a^{m+n}=a^m+a^n$

$\begin{aligned}\left(64 y^{100}\right)^{\frac{1}{2}} &=\sqrt[2]{64 y^{100}} \\&=\sqrt[2]{8^{2} y^{50} y^{50}} \\&=\sqrt[2]{8^{2}\left(y^{50}\right)^{2}} \\&=8 y^{50}\end{aligned}$

Hence, $8 y^{50}$ is equivalent to (64 y Superscript 100 Baseline) Superscript one-half.

8 0

3 years ago