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victus00 [196]
3 years ago
15

OO0is the sure test for magnetism.​

Physics
1 answer:
lara [203]3 years ago
8 0

Answer:

This is because , Repulsion takes place only between two likes poles of a magnet whereas attraction takes place between two unlike poles of a magnet and also between a magnet and a magnetic material .  So , repulsion is the sure test of magnetism .

Explanation:

OOP :P

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A car drives around a racetrack for 30 seconds. What do you need to know to
Irina18 [472]

To calculate the average speed of the car, we need

B. The total distance driven on the racetrack

Explanation:

The average speed of an object in motion is given by

speed = \frac{d}{t}

where

d is the distance covered by the object

t is the time interval considered to calculate the speed

The SI units of the speed are metres per second (m/s).

In this problem, we know the time interval:

t = 30 s

Therefore, in order to find the average speed, by looking at the equation we see that we also need the total distance driven by the car, so the correct answer is

B. The total distance driven on the racetrack

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

3 0
3 years ago
Number 11 please I really need help!!
vichka [17]

Answer:

Th answer is 1-

Explanation:

trust me i have this all on the periodic table thing my school gave lol

4 0
3 years ago
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The diagram above shows four light bulbs wired in a circuit. What would happen if bulb 3 burned out
andre [41]
The lights will no longer work because the circuit will be cut
6 0
3 years ago
Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.
ozzi

Answer:

The thrust is 6\times 10^6\ N

Explanation:

Given that,

Mass of gas, m=1.5\times 10^3\ kg

The rate at which the gas is expelling, \dfrac{dv}{dt}=4\times 10^{3}\ m/s

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

F=\dfrac{p}{t}

Also, p = mv

F=\dfrac{mv}{t}

So,

F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N

So, the thrust is 6\times 10^6\ N

3 0
4 years ago
Choose the correct statement below that accurately describes the shear and normal stresses in a beam. A. Shear stresses are maxi
Scorpion4ik [409]

Answer:

A. Shear stresses are maximum at the neutral axis and normal stresses are maximum furthest from the neutral axis.

Explanation:

Normal stress :

Normal stress is defined as the stress or the restoring force that occurs on the plane when an external axial load is applied on it. For a beam the normal stress is maximum at the point furthest from the neutral axis and is zero at the neutral axis of the beam.

Shear stress :

Shear stress is a stress which occurs when the force acts on the surface of the member in a parallel direction. It changes the shape of the member.  For a beam, the shear stress is maximum at the neutral axis.

6 0
3 years ago
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