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Vanyuwa [196]
3 years ago
14

The motion map shows an object’s position and velocity at given times. A long black arrow right labeled x. Above that are 5 gree

n arrows pointing right end to end and are the same length. There are two more green arrows each a little shorter. Farther up from the line is a point. Much farther above that are 3 green arrows each longer than the previous. How can the map be changed so it shows constant acceleration after the object changes direction? by adding vectors that are all the same length and placing them above the current top row of vectors by adding vectors that gradually increase in length and placing them above the current top row of vectors by adding vectors that are all the same length and placing them below the current bottom row of vectors by adding vectors that gradually increase in length and placing them below the current bottom row of vectors

Physics
2 answers:
Digiron [165]3 years ago
5 0

The map be changed <u>by adding vectors that are all the same length and placing them above the current top row of vectors</u>

<h3>Further explanation</h3>

A motion map represents the position, velocity, or acceleration of an object at various time readings

a small point or dot describes the position of the object. the object's velocity / acceleration is represented by an arrow / vector.

In this motion map, The arrows (vectors) are all the same length (same speed) and point in the same direction (direction to the right) for t = 0 (origin) to t = 4s

At t = 5s, the object has slowed down, and at t = 7s and 8s the object stops

At t = 9s-11 s, the object accelerates to the left

So the position of the next moving object will be above the previous movement, and the length of the same vector shows the same speed / acceleration

So that motion maps show constant acceleration after the object changes direction, it can be done by adding vectors that are all the same length and placing them above the current top row of vectors

<h3>Learn more</h3>

The initial velocity of the bird before the gust of wind

brainly.com/question/13207873

Keywords: motion map,  constant acceleration, dot, arrows, object,length, vectors, row

#LearnwithBrainly

Ad libitum [116K]3 years ago
5 0

Answer:

The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.v

Explanation:

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A seagull flies at a velocity of 9.00 m/s straight into the wind.
RideAnS [48]

a)If it takes the bird 18.0 minutes to fly 6 km away from the earth, the wind's speed will be 4 m/s.

b) The bird would need 7 minutes and 42 seconds to fly back 6 kilometers if he turned around and flew with the wind.

c)Compared to the 133.33 seconds it would take without the wind, the overall round-trip time is affected by the wind.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

A seagull flies at a velocity,\rm v_{SA}  = 9 \ m/sec

The time the bird takes,t=18.0 min

The distance traveled relative to the earth = 6.00 km

a)

The seagull's relative velocity with reference to the ground as;

\rm v_{sg} = \frac{6.00 \times 10^3 \ m }{(20 min) \times \frac{60 s }{1 \ min}} \\\\ v_{sg}= 5.00 \ m/sec

Air velocity with reference to the ground is;

\rm v_{AG}= v_{SG}-v_{SA} \\\\ v_{AG} = 5.00 \ m/sec - 9.00 \ m/sec \\\\ v_{AG} = -4.00 \ m/sec

b)

If the bird turns around and flies with the wind, The time will he take to return 6.00 km is;

\rm v_{SG}=v_{SA}+v_{AG} \\\\ v_{SG}=-900 \ m/sec +(-4.00 \ m/sec) \\\\ v_{SG}= -13.00 \ m/sec

The time the bird takes;

\rm t = \frac{x_{SG}}{v_{SG}} \\\\ t = \frac{6.00 \times 10^3 \ m }{13.00 \ m/sec } \\\\ t = 462 m/sec \\\\ t = 7  \ min \  and  \ 42  \ sec

c)\

The total round-trip time compared to what it would be with no wind. is;

\rm  t = 20 \ min( \frac{60 \ sec }{1 \ min} )+ 462 \ sec \\\\ t = 1200 \ sec +6 462 \ ec \\\\ t= 1662 \ sec

The time for the round trip is;

\rm  t = \frac{12 \times 10^ 3 }{ 9 \ m/sec }  \\\\ t  = 1333.33 \ sec

Hence the wind's speed, the time bird would need to fly back the total round-trip time will be  4 m/s, 7 minutes and 42 seconds and 1333.33 sec.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

4 0
2 years ago
What type of magnetism is generated when a current-carrying wire is wrapped around an iron core?
lakkis [162]
A simple electromagnet consisting of a coil of insulated wire wrapped around an iron core<span>. A </span>core<span> of ferromagnetic material like </span>iron<span> serves to increase the magnetic field created. The strength of magnetic field </span>generated<span> is proportional to the amount of </span>current<span> through the winding.</span>
5 0
3 years ago
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This term means that we are interacting with an item at a high-level, with lower-level internal details hidden from the user.
katovenus [111]

Option d) abstraction is the correct answer.

Abstraction is the process of taking away or removing characteristics from something in order to reduce it to a set of essential characteristics. In object-oriented programming, abstraction is one of three central principles Through this process, a programmer hides all but the relevant data about an object in order to reduce complexity and increase efficiency.

Learn more about Abstraction here:

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7 0
2 years ago
Suppose that the current in the solenoid is i(t). The self-inductance L is related to the self-induced EMF E(t) by the equation
Artemon [7]

Answer:

L =   μ₀ n r / 2I

Explanation:

This exercise we must relate several equations, let's start writing the voltage in a coil

        E_{L} = - L dI / dt

 

Let's use Faraday's law

       E = - d Ф_B / dt

in the case of the coil this voltage is the same, so we can equal the two relationships

        - d Ф_B / dt = - L dI / dt

The magnetic flux is the sum of the flux in each turn, if there are n turns in the coil

        n d Ф_B = L dI

we can remove the differentials

      n Ф_B = L I

magnetic flux is defined by

     Ф_B = B . A

in this case the direction of the magnetic field is along the coil and the normal direction to the area as well, therefore the scalar product is reduced to the algebraic product

      n B A = L I

the loop area is

      A = π R²

     

we substitute

       n B π R² = L I                    (1)

To find the magnetic field in the coil let's use Ampere's law

        ∫ B. ds = μ₀ I

where B is the magnetic field and s is the current circulation, in the coil the current circulates along the length of the coil

           s = 2π R

we solve

              B 2ππ R =  μ₀ I

              B =  μ₀ I / 2πR

we substitute in

       n ( μ₀ I / 2πR) π R² = L I

       n  μ₀ R / 2 = L I

       L =   μ₀ n r / 2I

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4 years ago
Whats the difference between an inner planet and an outer planet
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