5/12 - 1/4 equals help I'm so confused
2 answers:
You might be interested in
Answer:
A
Step-by-step explanation:
A good trick for trigonometric functions is to remember SOHCAHTOA:
Sin=<u>O</u>pposite over <u>H</u>ypotenuse
Cos=<u>A</u>djacent over <u>H</u>ypotenuse
Tan=<u>O</u>pposite over <u>A</u>djacent
The red arrows on the attachment indicate where opposite, hypotenuse, and adjacent are for angle A.
So in this case, the sin of angle A (opposite over hypotenuse) would be and cos A (adjacent over hypotenuse) would be
.
I hope this helps!
Answer:
m∠CEB is 55°
Step-by-step explanation:
Since ∠ADE = 55°, and ∠ADE is half of ∠ADC because ED bisects ∠ADC. Bisect means to cut in half.
∠ADC = 110° because it is double of ∠ADE.
Since AB║CD and AD║BC, the two sets of parallel lines means this shape is a parallelogram. In parallelograms, <u>opposite angles have equal measures</u>.
∠ADC = ∠CBE = 110°
All quadrilaterals have a sum of angles 360°. Since ∠DCB = ∠BAD and we know two of these other angles are each 110°:
360° - 2(110°) = 2(∠DCB)
∠DCB = 140°/2
∠DCB = ∠BAD = 70°
∠DCB was bisected by EC, which makes each divided part half.
∠DCE = ∠BCE = (1/2)(∠DCB)
∠DCE = ∠BCE = (1/2)(70°)
∠DCE = ∠BCE = 35°
All triangles' angles sum to 180°.
In ΔBCE, ∠BCE = 35° and ∠CBE = 110°.
∠CEB = 180° - (∠BCE + ∠CBE)
∠CEB = 180° - (35° + 110°)
∠CEB = 55°
Therefore m∠CEB is 55°.
