1/3 ( − 7/4 k +1) − 10/3 k = − 13/8

Does anyone know how many ways you can make 16 and 19 on a grid

sasho [114]

You can look for the number 16 on the x-axis. (bottom line) and put a finger there. Then, look for 19 on the y -axis (left line) and put a finger there. Trace your left finger to the right and your right hand up until they meet. That is (16,19)

8 0

2 years ago

Plzz help its so confusing

JulsSmile [24]

espero que sea de tu agrado la tarea que te estoy enviando

soy de peru

brillith2022

Download pdf

pdf

6 0

2 years ago

Name the property illustrated. (4 + 6) + 9 = 4 + (6 + 9)

Andrews [41]

Commutative property.
Mark brainliest

3 0

3 years ago

Solve through substitution –3x–8y=20 y=5x+19 Point of intersection, please

Sedaia [141]

Answer:

(-4, -1)

Step-by-step explanation:

-3x - 8y = 20; y = 5x + 19

y = 5x + 19; -3x - 8y = 20

y = 5x + 19

-3x - 8y = 20

-3x - 8(5x + 19) = 20

-43x - 152 = 20

-43x - 152 + 152 = 20 + 152

-43x = 172

-43x / -43 = 172 / -43

x = -4

y = 5x + 19

y = (5)(-4) + 19

y = -1

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

2 years ago