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grigory [225]
2 years ago
15

20 points if you answer

Mathematics
2 answers:
yulyashka [42]2 years ago
6 0

Answer:

The second stove had a higher temperature when the stoves were turned off.

The first stove cooled down at a faster rate.

Step-by-step explanation:

first stove: T(t) = 180 - 2.55t can also be written as T(t) = -2.55t + 180

(180 is the y-intercept; -2.55 is the slope)

second stove = T(t) = mt + 200

(0,200) (40,130)

\frac{200 - 130}{0 - 40} = \frac{60}{-40} = \frac{3}{-2} = -1.5

T(t) = -1.5t + 200

victus00 [196]2 years ago
4 0

Answer:

he is correct

Step-by-step explanation:

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A frustum is formed when a plane parallel to a cone’s base cuts off the upper portion as shown. Which expression represents the
Bezzdna [24]
Think of the two pieces together as a single cone of height 19, and its volume.
Then think of only the upper piece as a cone, and find its volume.
The volume of the frustum is the total volume minus the volume of the upper piece.

The volume of a cone is:

V = \dfrac{1}{3} \pi r^2 h

Total volume:

V_t = \dfrac{1}{3} \times \pi \times 7.5^2 \times 19

Volume of upper cone:

V_u = \dfrac{1}{3} \times \pi \times 3.5^2 \times 8

Volume of frustum:

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3 0
3 years ago
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7) Diego travels from Odessa to el Paso approximately 300 miles apart
bulgar [2K]

Answer:

≈3hrs 45mins

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1
Ratling [72]

Answer:

\sqrt3

Step-by-step explanation:

To find:

The value of tan60^\circ = ?

Solution:

Kindly consider the equilateral \triangle ABC as attached in the answer area.

Let the side of triangle = a units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = \frac{a}{2}

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\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}

Side AD = \frac{\sqrt3}{2}a

Using Trigonometric ratio:

tan\theta = \dfrac{Perpendicular}{Base}

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Putting the values of AD and BD:

tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}

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2 years ago
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Answer:

7

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