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Anastasy [175]
3 years ago
9

What is the answer? please tell me the correct answer

Mathematics
2 answers:
Nitella [24]3 years ago
6 0

Answer:

{35} square units

Step-by-step explanation:

To find the area of a parallelogram, multiply the base by the height.

Formula :- A = B × H

B→ Base

H→ height

Area of the parallelogram = Base × Height

→ Area= 5×7

→ 35

-------------

hope it helps...

have a great day!!

Alona [7]3 years ago
6 0

Answer:

The answer is 35. Its essentially a rectangle but a piece was moved.

Step-by-step explanation:

7x5=35

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99/1=99

Step-by-step explanation:

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Helpppp me pleaseeeeeeeeeee
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m<P = 27.5°

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3 years ago
prove the following identity: sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x please provide a proof in some shape form or fash
wolverine [178]

Answer:

Step-by-step explanation:

Hello,

<u><em>Is this equality true ?</em></u>

sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x

<u>1. let 's estimate the left part of the equation</u>

sec(x)csc(x)(tan(x) + cot(x)) =\dfrac{1}{cos(x)sin(x)}*(\dfrac{sin(x)}{cos(x)}+\dfrac{cos(x)}{sin(x)})\\\\=\dfrac{1}{cos(x)sin(x)}*(\dfrac{sin^2(x)+cos^2(x)}{sin(x)cos(x)})\\\\=\dfrac{1}{cos(x)sin(x)}*(\dfrac{1}{sin(x)cos(x)})\\\\\\=\dfrac{1}{cos^2(x)sin^2(x)}

<u>1. let 's estimate the right part of the equation</u>

<u />2+tan^2(x) + cot^2(x)=2+\dfrac{sin^2(x)}{cos^2(x)}+\dfrac{cos^2(x)}{sin^2(x)}\\\\=\dfrac{2cos^2(x)sin^2(x)+cos^4(x)+sin^4(x)}{cos^2(x)sin^2(x)}\\\\=\dfrac{(cos^2(x)+sin^2(x))^2}{cos^2(x)sin^2(x)}\\\\=\dfrac{1^2}{cos^2(x)sin^2(x)}\\\\=\dfrac{1}{cos^2(x)sin^2(x)}<u />

This is the same expression

So

sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x

hope this helps

7 0
3 years ago
What is 2x+5y=20 3x-10y=37
Maru [420]
I'm not sure how you want me to answer this question? WHat are you tryng to solve for?
7 0
3 years ago
Helppppp me please ASAP
Ymorist [56]

Answer:

5, 19, 21

Step-by-step explanation:

The sum of two smaller sides must be larger than the largest side in order to be a triangle. This means that only the first one can be a set of the triangle.

7 0
3 years ago
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