Answer:
x=7
Step-by-step explanation:
Simplifying
3x + 2(4 + 6x) = 113
3x + (4 * 2 + 6x * 2) = 113
3x + (8 + 12x) = 113
Reorder the terms:
8 + 3x + 12x = 113
Combine like terms: 3x + 12x = 15x
8 + 15x = 113
Solving
8 + 15x = 113
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + -8 + 15x = 113 + -8
Combine like terms: 8 + -8 = 0
0 + 15x = 113 + -8
15x = 113 + -8
Combine like terms: 113 + -8 = 105
15x = 105
Divide each side by '15'.
x = 7
Simplifying
x = 7
Answer:
160
Step-by-step explanation:
Muliply both sides by 20/3 to get e=20/3*24=160
Answer:
-2.26 lb
Step-by-step explanation:
Let the dog's initial weight be d.
Then, one year later, the dog weighs 3.73 lb less, and thus weighed d - 3.73 lb.
During the next year, the dog gained 1.47 lb, so now weighs d - 3.73 + 1.47 lb, or
d - 2.26 lb. This indicates a total weight loss of 2.26 over these two years.
We can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.
<h3>What is the extraneous solution?</h3>
In mathematics, an extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem, such as the answer to an equation.
As we know from the definition the extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem.
Let's suppose the equation is:

Squaring both the sides:
x + 4 = (x - 2)²
x + 4 = x² - 4x + 4
x² -5x = 0
x = 0 or x = 5
Checking for the solution by plugging in the equation;

3 = 3

2 ≠ -2
The solution x = 0 shows extraneous solution.
Thus, we can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.
Learn more about the extraneous solution here:
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