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MAXImum [283]
2 years ago
5

A researcher plans to investigate whether a cup of hot milk at night helps people relax so that they fall asleep quickly. in thi

s study, _____________.
a. the independent variable is the amount of time it takes the person to fall asleep
b. the independent variable is the lab in which the research is conducted.
c. the independent variable is the hot milk at bedtime
d. the independent variable is the hypothesis of the study.
Mathematics
1 answer:
padilas [110]2 years ago
8 0
C. the independent variable is the hot milk at bedtime
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Hello, I really struggle with math and I was wondering if you could help me with the following problem please? It will be much a
xz_007 [3.2K]

Answer:

x=7

Step-by-step explanation:

Simplifying

3x + 2(4 + 6x) = 113

3x + (4 * 2 + 6x * 2) = 113

3x + (8 + 12x) = 113

Reorder the terms:

8 + 3x + 12x = 113

Combine like terms: 3x + 12x = 15x

8 + 15x = 113

Solving

8 + 15x = 113

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + 15x = 113 + -8

Combine like terms: 8 + -8 = 0

0 + 15x = 113 + -8

15x = 113 + -8

Combine like terms: 113 + -8 = 105

15x = 105

Divide each side by '15'.

x = 7

Simplifying

x = 7

5 0
2 years ago
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HELP PLEAE GIVING BRAINLIEST! MEAN A LOT IF YOU HELP! :)<br> HELP SOLVE
Bumek [7]

Answer:

160

Step-by-step explanation:

Muliply both sides by 20/3 to get e=20/3*24=160

5 0
2 years ago
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Solve for x.
zubka84 [21]
The correct answer is 9
3 0
2 years ago
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The pet doctor weighs Marc's dog every year. Last year, the dog lost 3.73 pounds from the previous year. This year, the dog gain
levacccp [35]

Answer:

-2.26 lb

Step-by-step explanation:

Let the dog's initial weight be d.

Then, one year later, the dog weighs 3.73 lb less, and thus weighed d - 3.73 lb.  

During the next year, the dog gained 1.47 lb, so now weighs d - 3.73 + 1.47 lb, or

d - 2.26 lb.  This indicates a total weight loss of 2.26 over these two years.

6 0
2 years ago
How do you check is the equation is a extraneous solution pr not?
vampirchik [111]

We can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.

<h3>What is the extraneous solution?</h3>

In mathematics, an extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem, such as the answer to an equation.

As we know from the definition the extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem.

Let's suppose the equation is:

\rm \sqrt{x+4} = x -2

Squaring both the sides:

x + 4 = (x - 2)²

x + 4 = x² - 4x + 4

x² -5x = 0

x = 0 or x = 5

Checking for the solution by plugging in the equation;

\rm \sqrt{5+4} = 5 -2

3 = 3

\rm \sqrt{0+4} = 0 -2

2 ≠ -2

The solution x = 0 shows extraneous solution.

Thus, we can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.

Learn more about the extraneous solution here:

brainly.com/question/14054707

#SPJ1

6 0
2 years ago
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