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m_a_m_a [10]
3 years ago
12

The compression strength of concrete (the maximum pressure that can be exerted on the base of the structure) is 1.7 × 107 Pa. Wh

at is the height of the tallest cylindrical concrete pillar with a radius of 46 cm that will not collapse under its own weight?
Physics
1 answer:
yarga [219]3 years ago
8 0
<h2>Height of cylinder = 679.70 m</h2>

Explanation:

Compression strength = 1.7 x 10⁷ Pa

Normal force = Compression strength x Area

Radius = 46 cm = 0.46 m

Area of cylinder = π x 0.46² = 0.665 m²

Normal force =  1.7 x 10⁷ x 0.665 = 1.13 x 10⁷ N

So weight of cylinder = 1.13 x 10⁷ N

Density of concrete = 25 kN/m³ = 25000 N/m³

Volume of cylinder = Base area x Height = 0.665 x h

Weight of cylinder = 25000 x 0.665 x h

Equating

            25000 x 0.665 x h = 1.13 x 10⁷

                   h = 679.70 m

Height of cylinder = 679.70 m

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Answer:

Their number should increase

Explanation:

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How do very high density objects appear in an ultrasound?
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a cylinder has a radius of 2.1cm and a length of 8.8cm .total charge 6.1 x 10^-7C is distributed uniformly throughout. the volum
7nadin3 [17]

The answer for the following problem is explained below.

Therefore the volume charge density of a substance (ρ) is 0.04 × 10^{-1} C.

Explanation:

Given:

radius (r) =2.1 cm = 2.1 ×10^{-2} m

height (h) =8.8 cm = 8.8 ×10^{-2} m

total charge (q) =6.1×10^{-7} C

To solve:

volume charge density (ρ)

We know;

<u> ρ =q ÷ v</u>

volume of cylinder = π ×r  × r × h

volume of cylinder =3.14 × 2.1 × 2.1 ×10^{-4} × 8.8 ×10^{-2}

volume of cylinder (v) = 122.23 ×10^{-6}

<u> ρ =q ÷ v</u>

ρ = 6.1×10^{-7} ÷   122.23 ×10^{-6}

<u>ρ = 0.04 × </u>10^{-1}<u> C</u>

Therefore the volume charge density of a substance (ρ) is 0.04 × 10^{-1} C.

3 0
3 years ago
Three resistors of resistances, R1=10Ω, R2=5Ω, R3=20Ω are connected in a circuit in such way that same amount of current flows t
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Answer

Explanation:

As the three resistors are connected in series, the expression to be used for the  

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We perform the mathematical operations that lead us to the result we are looking for:  

RT - 30Ω

5 0
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