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Viktor [21]
3 years ago
13

Two gliders collide on a frictionless air track that is aligned along the x axis. Glider A has an initial velocity of +4.0 m/s a

nd a mass of mA = 0.20 kg. Glider B is initially at rest and has a mass mB. After they collide, A has a velocity of -1.0 m/s and B has a velocity of +2.0 m/s. Determine mB. Assume that It is an elastic collision.
Physics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

As collision is elastic,thus we can use conservation of momentum equation

mA=0.2 kg

(vB)1=0 m/s.......................as it is on rest before collision

(vA)1=4 m/s

(vA)2=-1 m/s

(vB)2=2 m/s

using equation

(mA*vA+mB*vB)1= (mA*vA+mB*vB)2

Where 1 and 2 represents before and after collision

(0.2*4)+(mB*0)=(0.2*-1)+(mB*2)

0.8=-0.2+(2mB)

mass of object B=mB=0.3 Kg

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Dmitriy789 [7]

Answer:

75 miles an hour

I hope this is correct and helps

3 0
3 years ago
The mass of an object with 500 J of kinetic energy moving with a velocity of 5 m/s is
Ann [662]

40kg

Explanation:

Given parameters:

Kinetic energy  = 500J

Velocity = 5m/s

Unknown:

Mass of the object = ?

Solution:

Kinetic energy is the energy due to motion of a body. It is expressed as:

          K.E = \frac{1}{2} mv²

  m is the mass of the body

  v is the velocity

 To find the mass, make it the subject of the expression:

         m = \frac{2 K.E}{v[tex]^{2}}[/tex]

          m =   \frac{2 x 500}{5[tex]^{2}}[/tex] = 40kg

Learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

4 0
4 years ago
What is true for ALL of the examples of electromagnetic waves?
nasty-shy [4]
A they all move the same speed in a vacuum this is because in a the photons don't bump in to anything
5 0
3 years ago
When antimatter interacts with an equal mass of ordinary matter, both matter and antimatter are converted completely into energy
Ilya [14]

Answer:

  v = 5.88 10⁷ m / s

Explanation:

For this exercise we use the relation

          E = m c²

also indicate that all energy is converted into kinetic energy

          E = K = ½ (M-2m) v²

where m is the mass of antimatter and M is the mass of the ship's mass. Factor two is due to the fact that equal amounts of matter and antimatter must be combined

we substitute  

         m c² = ½ (M-2m) v²

        v² = 2 \frac{m}{M+2m} \ c^2

         

let's calculate

        v = \sqrt{2 \  \frac{4 \ 10^4 }{2 \ 10^6 + 2 \ 4 \ 10^4} \ (3 \ 10^8)^2}

         v = \sqrt{ 34.615 \ 10^{14}}

        v = 5.88 10⁷ m / s

8 0
3 years ago
What percentage of Earth is covered with water?<br><br> 97<br> 70<br> 3<br> 3.5<br> 20<br> 69
Leni [432]

Answer:

70 percent

Explanation:

the answer is 70 percent

7 0
3 years ago
Read 2 more answers
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