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Free_Kalibri [48]
2 years ago
10

Why is the gravitational potential energy of an object 1 meter above Earth's surface more than its potential energy 1 meter abov

e the moon's surface?
A. The object’s mass is less on the Earth.
B. The object’s weight is more on the moon.
C. The object’s acceleration due to gravity is more on the Earth.
D. both a and c
Physics
1 answer:
Umnica [9.8K]2 years ago
3 0
I Believe The Answer Is C
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What is static and sliding friction
vodka [1.7K]
Static friction is the friction that exists between a stationary object and the surface on which it's resting.
frictional force occurs when you try to push an object alongside a surface.
5 0
2 years ago
How many electrons must be removed from each of two 5.69-kg copper spheres to make the electric force of repulsion between them
CaHeK987 [17]

Answer:

n=3.056*10^{9} Electrons

Explanation:

Please see attached file

7 0
3 years ago
The parachute on a drag racing car deploys at the end of a run. If the car has a mass of 820 kg and the car is moving 36 m/s, wh
Lelechka [254]

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

v^2=v^2_o-2ax

where,

v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}

Next, consider that the formula for the force is:

F=ma

where,

m: mass of the car = 820 kg

a: deceleration of the car = 0.66m/s^2

Replace the previous values and simplify:

F=(820kg)(0.66\frac{m}{s^2})=542.20N

Hence, the required force to stop the car is 542.20N

4 0
1 year ago
Ohm's law states which relationship between electrical quantities? a. Volts = current x resistance b. Volts = current divided by
miv72 [106K]

Answer:

a. Volts = current x resistance

Explanation:

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

V = IR

Where;

V represents voltage measured in voltage.

I represents current measured in amperes.

R represents resistance measured in ohms.

Hence, Ohm's law gives the relationship between voltage, current and resistance of an electric circuit.

7 0
2 years ago
What is the voltage output (in V) of a transformer used for rechargeable flashlight batteries, if its primary has 475 turns, its
VMariaS [17]

Answer:

Output voltage is 1.92 volts.

Explanation:

Given that,

Number of turns in primary coil, N_p=475

Number of turns in secondary coil, N_s=8

Input voltage, V_i=114\ V

We need to find the voltage output of a transformer used for rechargeable flashlight batteries. For a transformer, the number of turns and the voltage ratio is given by :

\dfrac{N_p}{N_s}=\dfrac{V_i}{V_o}\\\\\\V_o=114\cdot\dfrac{8}{475}\\\\V_o=1.92\ V

So, the output voltage is 1.92 volts.

3 0
3 years ago
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