<span>Dayson has 1 m2 of wrapping paper, which is 10000 cm2:
1 m = 100 cm
1 m^2 = (100 cm)^2
</span>1 m^2 = 10000 cm^2
<span>The package has a surface area of cm2:
A = 2*(50*20) + </span>2*(50*18) + 2*(18*20)
A = <span>
<span>4520 cm^2
</span></span>The area of the package is less than the area of the wrapping paper (4520 cm^2 < 10000 cm^2<span>). So, Dayson cover the package with the wrapping paper.</span>
Answer:
- 3x + 1
Step-by-step explanation:
10) g(n) = -21+ 3n; Find gl-6)
A) 152
B) -20
C) 1
D) 90
Your answer would be B
If this helped can I please get brainliest
Let S and B be savings and bills respectively. Then,
S α 1/B
S = k/B Where k = Constant.
When S = $300, B = 65
Then,
300 = k/65
k = 300*65 = 19500
Therefore,
For B = $145,
S= 19500/145 = $134.48
The answer is 8 because if you divide 52 by 4 it gives 13, do the same to the top and you get 8
