Articles of clothing that the store received last Thursday is 84
<u>Solution:</u>
Given that
A clothing donation store received numerous articles of clothing on Thursday of last week.
The number of articles of clothing that the store received last Thursday is represented by the following expression:
4 (3x − 1) − 2 (6 + 2x)
Need to calculate articles of clothing that the store received last Thursday when x = 12.5
As on Thursday x = 12.5, need to substitute x = 12.5 in above equation to get number of articles received on Thursday.
On substituting x = 12.5, we get
4 ( (3 x 12.5 ) – 1 ) – 2 ( 6 + ( 2 x 12.5 ) )
=> 4 (37.5 – 1) – 2 (6 + 25)
=> 146 – 62 = 84
On substituting x = 12.5 , we are getting value of expression as 84.
Hence articles of clothing that the store received last Thursday is 84
Answer:
Step-by-step explanation:
Remark
Simple answer: you can't. I mean that you can't try to use 4 numbers, but you can solve the problem. You are going to have to redraw the diagram on another sheet of paper. Follow the directions below.
Directions for diagram extension.
Go to the right hand end of the 10 unit line.
Draw a line from the intersection point of the 10 unit line and 12 unit line
Draw this line so it is perpendicular to the 18 unit line. That will mean that the new line is parallel (and equal) to x
Mark the intersect point of the new line and the 18 unit line as B
Mark the intersect point of the 18 point line and the 12 unit line as C
Given and constructed
BC = 18 - 10 = 8
BC is one leg of the Pythagorean triangle.
The new x is the other leg of the Pythagorean triangle.
12 is the hypotenuse.
Formula
x^2 + 8^2 = 12^2
x refers to the new x which is equal to the given x
Solution
x^2 + 64 = 144 Subtract 64 from both sides
x^2 +64 - 64 = 144-64 Combine
x^2 = 80 Break 80 down.
x^2 = 4 * 4 * 5 Take the square root of both sides
x = 4*sqrt(5)
Comment
If you want the area it is 4*sqrt(5)(10 + 18)/2 = 56*sqrt(5)
Answer:
11/4
Step-by-step explanation:
2 times 4 equals 8 and plus 3 equals 11 and dem is 4 so 11/4
Answer:
15) ∠BCD = 1/2 short arc BC = (360° -260°)/2 = 50° (C)
16) ∠K is supplementary to short arc JL = 180° -120° = 60° (C)
17) ∠V is half the difference of long arc TW and short arc UW.
.. (198° - UW)/2 = 69°
.. 198° -138° = UW = 60° (C)
18) ∠L is supplementary to short arc KM
.. KM = 180° -66° = 114° (C)
Step-by-step explanation: hope it helped
