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ryzh [129]
3 years ago
5

Compare the weight of a 5.00-kg object on Earth’s surface to the gravitational force between a 5.00-kg object that is one Earth

radius from another object of mass equal to 5.98 × 10 24 kg . Use Newton’s universal law of gravitation for the second part of the question
Physics
1 answer:
makkiz [27]3 years ago
5 0

Answer

given,

mass of an object = 5 Kg

mass of the other object = 5.98 x 10²⁴ Kg

radius of earth = 6371 Km = 6.371 x 10⁶ m

comparison between gravitational force between two object and weight of the object.

gravitational force between two objects

   F = \dfrac{Gm_1m_2}{r^2}

   F = \dfrac{6.67 \times 10^{-11}\times 5 \times 5.98 \times 10^{24}}{(6.371 \times 10^6)^2}

      F = 49.134 N

weight of the object on the earth surface

  F = m g

  F = 5 x 9.81

  F = 49.05 N

From the above two calculation we can conclude that gravitational force is approximately equal to weight of the body.

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3 years ago
The force per meter between the two wires of a jumper cable being used to start a stalled car is 0.244 N/m. (a) What is the curr
MakcuM [25]

Answer: current I is 144amp(A)

Explanation: The force per lenght F/L, current l, and separation distance r are related by the formula

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Permeability of free space is 1.257*EXP {-6} Henry/meter

F/L is 0.244 N/m, pi is 3.142,

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I is what we are looking for.

Now we have after substitution,

0.244

= 1.257*EXP {-6} * I²/(2*3.142*0.017)

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