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lys-0071 [83]
3 years ago
8

A baseball is thrown straight up. the drag force is proportional to v2. part a in terms of g, what is the y-component of the bal

l's acceleration when its speed is half its terminal speed and it is moving up?
Physics
1 answer:
steposvetlana [31]3 years ago
7 0

At the position of terminal speed the net acceleration of the ball will become zero

As we know that terminal speed will always reach when net force on the ball is zero and its speed will become constant.

So here at this position we can say

F_d = F_g

kv^2 = mg

v =\sqrt{\frac{mg}{k}}

now when ball is moving at half of the terminal speed in upward direction then net force on the ball in downwards direction will be

F_{net} = mg + F_d

F_{net} = mg + kv^2

here speed of the ball is half of the terminal speed

v = \frac{1}{2}*\sqrt{\frac{mg}{k}}

then we have

F_{net} = mg + k*\frac{mg}{4k}

F_{net} = \frac{5mg}{4}

now acceleration will be given as

a = \frac{F_{net}}{m}

now we have

a = \frac{5g}{4}

a = 12.25 m/s^2 downwards

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