Answer:
2 molecules of ATP and 2 molecules of NADH
Explanation:
Glycolysis is the first step of cellular respiration (break down of glucose to extract energy) which occurs in the cytoplasm. Glycolysis is a pathway common to all living organisms- prokaryotes and eukaryotes, as it does not require oxygen to occur.
Glycolysis occurs in two major phases (ten steps) requiring 10 enzymes catalyzing each step; the energy-requiring phase and the energy-requiring phase.
In the energy-requiring phase, the starting molecule (glucose) gets rearranged in a series of chemical reactions, and two phosphate groups gets attached to it producing fructose-1,6-bisphosphate which is unstable, This modified sugar then splits in half due to its instability to form two different but inter-convertible phosphate-bearing three-carbon sugars (Dihydroxyacetonephosphate, DHAP and Glyceraldehyde-3-phosphate, G3P). Because the phosphates used in these steps come from 2 ATP molecules, 2 ATP molecules get used up in this phase
All the DHAP molecules get converted to G-3-P in order to enter the next phase.
In the energy-recovering phase, the 3-carbon sugar (G3P) is converted into another three-carbon molecule called pyruvate, through a series of reactions. In these reactions, two ATP and 1 NADH molecules are made. This recovery phase occurs twice (one for each of the two isomeric three-carbon sugars, DHAP and G3P). Hence, a total of 4 ATP and 2 NADH molecules are produced in this phase.
Overall, Glycolysis converts one glucose (six-carbon) molecule to two pyruvate (three-carbon) molecules and a net release of 2 ATP molecules (4 overall - 2 used) and 2 NADH molecules.
Answer:
this is true
Explanation:
if it isnt in the leaves of a plant, then its in the stem, or maybe, the entire thing is green!
flowers have green stems, trees have green leaves, lily pads are green, etc.
hope this helped
Because for female sex link desease would require X°X° but for male X°Y so during crossing X linked dear are more common in male.
Answer:
This was the only treatment options adopted for the Ebola in 1995 in the Democratic Republic of Congo. The assumption was that immune response is generated by the virus in the WBC of the infected individuals. These response produce antibodies.
A total if 8 patients were transfused with these blood contained antibodies, but one of these died, the remaining 7 patients survived.
The antibodies were believed to have multiplied(produced b-cells) to neutralize the Ebola virus(antigens) and to ensure the survival of the patients
Explanation: