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Mashutka [201]
2 years ago
15

Given g(x)=5x+2, find g(-6)

Mathematics
2 answers:
kkurt [141]2 years ago
7 0
Bcfvn. BBC bmbbc. B b vhjvchxcj church. Hvhvychbycycbffjctccycycvidycgdfrghfdhfhfhfgkepfgogigugbhvgvyvjvufbinibunobinib k hvugycvbjjvuvcubjch gju furyfucfyfjcufrdifjfcjj
Temka [501]2 years ago
5 0

Answer:

Please refer to the attachment

Hope it helps

Please mark me as the brainliest

Thank you

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7. Estimote the following percentages of 60.<br> 10% =<br> 25% =<br> 50% =<br> 20% =
Orlov [11]

Answer:

10% of 60 = 6

25% of 60 = 15

50% of 60 = 30

20% of 60 = 12

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ &lt; 360°.
inna [77]

Answer:

First part

The answer is (5 square root 2, 45°), (-5 square root 2, 225°) ⇒ answer (d)

Second part

The equation in standard form for the hyperbola is y²/81 - x²/19 = 1 ⇒ answer(b)

Step-by-step explanation:

First part:

* Lets study the Polar form and the Cartesian form

- The important difference between Cartesian coordinates and

  polar coordinates:

# In Cartesian coordinates there is exactly one set of coordinates

  for any given point.

# In polar coordinates there is an infinite number of coordinates

   for a given point. For instance, the following four points are all

   coordinates for the same point.

# In the polar the coordinates the origin is called the pole, and

  the x axis is called the polar axis.

# The angle measurement θ can be expressed in radians

   or degrees.

- To convert from Cartesian Coordinates (x , y) to

  Polar Coordinates (r , θ)

# r = ± √(x² + y²)

# θ = tan^-1 (y / x)

* Lets solve the problem

- The point in the Cartesian coordinates is (5 , 5)

∵ x = 5 and y = 5

∴ r = ± √(5² + 5²) = ± √50 = ± 5√2

∴ tanФ = (5/5) = 1

∵ tanФ is positive

∴ Angle Ф could be in the first or third quadrant

∵ Ф = tan^-1 (1) = 45°

∴ Ф in the first quadrant is 45°

∴ Ф in the third quadrant is 180 + 45 = 225°

* The answer is (5√2 , 45°) , (-5√2 , 225°)

Second part:

* Lets study the standard form of the hyperbola equation

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the y-axis is

  y²/a² - x²/b² = 1, where

• the length of the transverse axis is 2a

• the coordinates of the vertices are (0 , ±a)

• the length of the conjugate axis is 2b

• the coordinates of the co-vertices are (±b , 0)

•      the coordinates of the foci are (0 , ± c),  

• the distance between the foci is 2c, where c² = a² + b²

* Lets solve our problem

∵ The vertices are (0 , 9) and (0 , -9)

∴ a = ± 9 ⇒ a² = 81

∵ The foci at (0 , 10) , (0 , -10)

∴ c = ± 10

∵ c² = a² + b²

∴ (10)² = (9)² + b² ⇒ 100 = 81 + b² ⇒ subtract 81 from both sides

∴ b² = 19

∵ The equation is  y²/a² - x²/b² = 1

∴  y²/81 - x²/19 = 1

* The equation in standard form for the hyperbola is y²/81 - x²/19 = 1

3 0
3 years ago
Angles EDF and FDH are
storchak [24]

Answer:

Can you get a picture please or more detail...

4 0
3 years ago
Read 2 more answers
Please help me this is due today
Evgen [1.6K]
Split the room into 2 rectangles 
area =  5*4 + 3*3  = 29 sq ft

So the cost is 29*8 =  $232
6 0
3 years ago
Problems 40-45 I need assistance with​
Greeley [361]

40. Multiply each row in the first matrix by each column in the second matrix.

The answer would be C.

41. E. Matrix

42. D. Transformations

43. C. determinants

44. B. equal matrices

45. A. Zero matrix

7 0
3 years ago
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