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3 years ago

Write an inequality for the following situation: Sam has less than $5 in his pocket. (Let $ x = amount of money in his pocket.)

Mathematics

2 answers:

Bess [88]3 years ago

7 0

Answer:

x < 5

Step-by-step explanation:

Sam has less than we would be <

The amount in his pocket would be x stating that x is less than

Now we add the five at the end fishing up the inequality to be x < 5

ValentinkaMS [17]3 years ago

5 0

Answer i well say 36

Step-by-step explanation:

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Vikentia [17]

For Question 6 is X=12 because you divide both sides which is 2 and 24 and you get 12, hope this helps

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3 years ago

How many attended the basketball game but did not attend the school play

Nata [24]

Answer:

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Step-by-step explanation:

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4 years ago

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Expand the given power using the Binomial Theorem. (10k – m)5

agasfer [191]

Answer:

$(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

$(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}$

∵ The binomial is $(10k-m)^{5}$

∴ a = 10k , b = -m and n = 5

∴ $(10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}$

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ $(10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})$

∴ $(10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

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3 years ago

13 inches = __ ft<br> PLS HELP PLS

Radda [10]

Answer:

1.083

Step-by-step explanation:

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3 years ago

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solve the system of equations using substitution. 3 multiplied by y equals negative the quantity 1 divided by 2 end of quantity

Bas_tet [7]

3y = -1/2x + 2 . . . . . . . . (1)
y = -x + 9 . . . . . . . . (2)
substituting (2) into (1), we have
3(-x + 9) = -1/2x + 2
-3x + 27 = -1/2x + 2
-1/2x + 3x = 27 - 2
5/2x = 25
x = (2 x 25)/5
x = 10
From (2)
y = -10 + 9
y = -1
solution (10, -1)

6 0

4 years ago