F(3)=4x-2 <br> F(1/2)=4x-2<br> F(-5)=4x-2

quester [9]

Answer:

Q matches to a and P matches to b

Step-by-step explanation:

This is a volume question so we can use the volume of a cylinder to see which one corresponds to what. Volume of a cylinder is $\pi$ $r^{2}$ h. We know that the heights of the cylinders are the same since the diagram says so. We also know pi is the same since thats a constant. The only thing thats different is the radius (as you can see radius of P is bigger than Q). If the radius of P is bigger than Q and all the other things are the same (height is the same and pi is the same), then that automatically means that P has more volume than Q. More volume means more time to fill up. Since Q has less volume, it will take less time to fill up. So now we look at the graph. A shows that the height of water increases at a faster rate than that of B. This is because there is less volume in that container (less volume=less time to fill up). Therefore a matches to Q and therefore b matches to P

3 0

2 years ago

A doctor at a local hospital is interested in estimating the birth weight of infants. How large a sample must she select if she

Nataly_w [17]

Answer:

The minimum sample size needed is $n = (\frac{1.96\sqrt{\sigma}}{4})^2$ . If n is a decimal number, it is rounded up to the next integer. $\sigma$ is the standard deviation of the population.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample must she select if she desires to be 90% confident that her estimate is within 4 ounces of the true mean?

A sample of n is needed, and n is found when M = 4. So

$M = z\frac{\sigma}{\sqrt{n}}$

$4 = 1.96\frac{\sigma}{\sqrt{n}}$

$4\sqrt{n} = 1.96\sqrt{\sigma}$

$\sqrt{n} = \frac{1.96\sqrt{\sigma}}{4}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{\sigma}}{4})^2$

$n = (\frac{1.96\sqrt{\sigma}}{4})^2$

The minimum sample size needed is $n = (\frac{1.96\sqrt{\sigma}}{4})^2$ . If n is a decimal number, it is rounded up to the next integer. $\sigma$ is the standard deviation of the population.

4 0

2 years ago

Classify the triangle with angles measuring 1130, 47°, and 20°.

nydimaria [60]

Answer:

<em>D. Obtuse</em>

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Use Green's Theorem to evaluate the line integral along the given positively oriented curve.

FromTheMoon [43]

Answer:

∫ C ( y + e√x) dx + ( 2x + cosy² ) dy = 1/3

Step-by-step explanation: See Annex

Green Theorem establishes:

∫C ( Mdx + Ndy ) = ∫∫R ( δN/dx - δM/dy ) dA

Then

∫ C ( y + e√x) dx + ( 2x + cosy² ) dy

Here

M = 2x + cosy² δM/dy = 1

N = y + e√x δN/dx = 2

δN/dx - δM/dy = 2 - 1 = 1

∫∫(R) dxdy ∫∫ dxdy

Now integration limits ( see Annex)

dy is from x = y² then y = √x to y = x² and for dx

dx is from 0 to 1 then

∫ dy = y | √x ; x² ∫dy = x² - √x

And

∫₀¹ ( x² - √x ) dx = x³/3 - 2/3 √x |₀¹ = 1/3 - 0

∫ C ( y + e√x) dx + ( 2x + cosy² ) dy = 1/3

5 0

2 years ago

A self own company charges $40 per month +0.05 cents for each text message sent.Select expression is there a percent of cost in

kondaur [170]

<h3>The monthly cost of cell phone is A = 40 + 0.005 m</h3>

Step-by-step explanation:

The monthly fixed charges by mobile company = $40

The cost of sending each text message = 0.05 cents

Now, 100 cents = 1 dollar

⇒ 1 cent =$ $(\frac{1}{100} )$

⇒ 0.05 cent s =$ $(\frac{1}{100} \times 0.05) =0.0005$

Also, the number of text messages send = m

So, the cost of sending m text message = m x ( cost of 1 text )

= m x ( $ 0.0005) = 0.0005 m

Now, Total bill = Fixed rate + cost of m texts

⇒ A =$40 + $ 0.0005 m

Hence, the monthly cost of cell phone is A = 40 + 0.005 m

7 0

3 years ago

F(3)=4x-2 F(1/2)=4x-2 F(-5)=4x-2