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3 years ago

If "-3<" x/5 < "-1" what is the value of x

Mathematics

1 answer:

Natalka [10]3 years ago

7 0

Answer:

-15 < x < -5

Step-by-step explanation:

-3 < x/5 < -1

Multiply all sides by 5

-3*5 < x/5 *5 < -1*5

-15 < x < -5

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A large university accepts 50% of the students who apply. Of the students the university accepts, 35% actually enroll. If 10,

lara31 [8.8K]

Answer:

3,500 students

Equation:

0.35 x 10,000 = 3,500

8 0

3 years ago

At a school, 129 students play at least one sport. This is 30% of the students at the school. How many students are at the sc

kkurt [141]

129/x=30/100
30x=12900
x=430
430 students

3 0

3 years ago

2x + a = 2x -3 in the equation above, a is a constant l. for what value of a does the equation have no solutions?

xenn [34]

A=-3 and i think any value of 'a' makes those equation infinite solution because expression has same variable both side.

4 0

3 years ago

g An irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the

blagie [28]

Answer:

A 90% confidence interval of the true mean is [$119.86, $123.34].

Step-by-step explanation:

We are given that an irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the mean amount of money spent on textbooks was $121.60.

Also, the standard deviation of the population was $6.36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean amount of money spent on textbooks = $121.60

$\sigma$ = population standard deviation = $6.36

n = sample of students = 36

$\mu$ = population mean

Here for constructing a 90% confidence interval we have used One-sample z-test statistics as we know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level

of significance are -1.645 & 1.645}

P(-1.645 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.645) = 0.90

P( $-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $121.60-1.645 \times {\frac{6.36}{\sqrt{36} } }$ , $121.60+1.645 \times {\frac{6.36}{\sqrt{36} } }$ ]

= [$119.86, $123.34]

Therefore, a 90% confidence interval of the true mean is [$119.86, $123.34].

5 0

3 years ago

Find the perimeter of the image below: Figure QRSTU is shown. Q is at 2, 0. R is at 4, 5. S is at 8, 7. T is at 6, 4. U is at 10

scoray [572]

The answer should be 26.1.

4 0

3 years ago