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3 years ago

In the reaction below, how would adding more of reactant A offect the equilibrium of the system? (2 points)

Chemistry

1 answer:

WARRIOR [948]3 years ago

8 0

Answer:

Shift it to the right toward the products,

Explanation:

Adding more reactant will increase the concentration of the reactants, to offset this increased concentration, more products will be formed.

An increase in concentration of a specie favors the direction that uses up that specie and lowers its concentration.
If the concentration of the species on the LHS is increased , the equilibrium will shift to the right to maintain the constancy of the equilibrium constant.

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This family (ethane, propane, butane, etc) of materials is likely to have what set of properties?

Ilya [14]

This family (ethane, propane, butane, etc) of materials is likely to have following set of properties.

The alkanes are non- polar solvents.
The alkanes are immiscible in water but freely miscible in other non-polar solvent .
The alkanes are consisting of weak dipole dipole bonds can not breaks the strong hydrogen bond.
The alkanes having only carbon (C) and hydrogen (H) atom which is bonded by a single bonds only.
The alkanes posses weak force of attraction that is weak van der waals force of attraction.

The ethane, propane, butane, belong to alkanes family.The alkanes are also considers as saturated hudrocarbons. Ethane is found in gaseous stae Ethane is the second alkane followed by propane followed by butane.

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7 0

1 year ago

_Li + __F2 → _LIF<br> How do I balance this?

Semmy [17]

Answer:

2Li + F₂ → 2LiF

Explanation:

The reaction expression is given as:

Li + F₂ → LiF

We are to balance the expression. In that case, the number of atoms on both sides of the expression must be the same.

Let use a mathematical approach to solve this problem;

Assign variables a,b and c as the coefficients that will balance the expression:

aLi + bF₂ → cLiF

Conserving Li: a = c

F: 2b = c

let a = 1, c = 1 and b = $\frac{1}{2}$

Multiply through by 2;

a = 2, b = 1 and c = 2

2Li + F₂ → 2LiF

5 0

3 years ago

YO I NEED HELP!!!! APEX PLEASE

podryga [215]

B is the correct answer for it

8 0

2 years ago

Read 2 more answers

How many grams are in 4 moles of Calcium?

mixer [17]

Answer:

160.32 grams of Ca or 160 if rounded

Explanation:

Multiply moles of Ca by the conversion factor (molar mass of calcium) 40.08 g Ca/ 1 mol Ca, which then allows the cancelation of moles, leaving grams of Ca.

4 mol*40.08g/mol = 160.32 grams of Ca

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3 0

2 years ago

Read 2 more answers

Which of the following statements describes the correct method of preparation of 1.00 L of a 2.0 M urea solution?

Zolol [24]

Answer:

To prepare 1.00 L of 2.0 M urea solution, we need to dissolve 120 g of urea in enough water to produce a total of 1.00 L solution

Explanation:

Molarity of a solute in a solution denotes number of moles of solute dissolved in 1 L of solution.

So, moles of urea in 1.00 L of a 2.0 M urea solution = 2 moles

We know, number of moles of a compound is the ratio of mass to molar mass of that compound.

So, mass of 2 moles of urea = $(2\times 60.06)g=120 g$

Therefore to prepare 1.00 L of 2.0 M urea solution, we need to dissolve 120 g of urea in enough water to produce a total of 1.00 L solution

So, option (C) is correct.

8 0

3 years ago