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3 years ago

In the reaction below, how would adding more of reactant A offect the equilibrium of the system? (2 points)

Chemistry

1 answer:

WARRIOR [948]3 years ago

8 0

Answer:

Shift it to the right toward the products,

Explanation:

Adding more reactant will increase the concentration of the reactants, to offset this increased concentration, more products will be formed.

An increase in concentration of a specie favors the direction that uses up that specie and lowers its concentration.
If the concentration of the species on the LHS is increased , the equilibrium will shift to the right to maintain the constancy of the equilibrium constant.

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What is the difference between a mixture, a solution, and a pure substance?

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3 years ago

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If a solution contains 3 moles/liter of sodium chloride (nacl, made of sodium ions and chloride ions), what is the osmolarity of

valkas [14]

Answer: Osmolarity of the sodium chloride solution is 18 Osmol/L.

Explanation:

Osmolarity is defined as the the concentration of the solution which is expressed as the total number of solution particles present in one liter of solvent.

We are given the molarity of the solution which is 3mol/L and to convert it into osmolarity, we will multiply the number of osmoles that are produced by the solute.

Osmole is defined as the particles that contribute to the osmotic pressure of a solution.

The solute given here is sodium chloride (NaCl). Number of osmoles can be determined by the dissociation of this solvent into ions.

The equation given by the dissociation of NaCl:

$NaCl\rightarrow Na^++Cl^-$

1 mole of sodium chloride produces 2 moles of ions.

So, 3 moles of sodium chloride will produce = (3 × 2) = 6 moles of ions.

Hence, osmolarity of the sodium chloride solution will be $6\times 3mol/L=18Osmol/L$

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3 years ago

How many milliliters of 0.100 m naoh are required to neutralize 9.00 ml of 0.0500 m hcl?

BabaBlast [244]

V ( NaOH ) = mL ?

M ( NaOH ) = 0.100 M

V ( HCl ) = 9.00 mL / 1000 => 0.009 L

M ( HCl ) = 0.0500 M

number of moles HCl:

n = M x V

n = 0.009 x 0.0500 => 0.00045 moles HCl

mole ratio:

HCl + NaOH = NaCl + H2O

1 mole HCl ---------------- 1 mole NaOH
0.00045 moles HCl ----- ??

0.00045 x 1 / 1 => 0.00045 moles of NaOH

M = n / V

0.100 = 0.00045 / V

V = 0.00045 / 0.100

V = 0.0045 L

1 L ------------ 1000 mL
0.0045 L ----- ??

0.0045 x 1000 / 1 => 4.5 mL of NaOH

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Answer:

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Explanation:

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