Which half-reaction correctly describes an oxidation?
2 answers:
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<u>Answer:</u> The final temperature of the system is 14.60°C
<u>Explanation:</u>
When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.
The equation used to calculate heat released or absorbed follows:
......(1)
where,
q = heat absorbed or released
= mass of aluminium = 25.00 g
= mass of water = 100 g
= final temperature = ?°C
= initial temperature of aluminium = 100°C
= initial temperature of water = 10°C
= specific heat of aluminium = 0.900 J/g°C
= specific heat of water= 4.18 J/g°C
Putting values in equation 1, we get:
Hence, the final temperature of the system is 14.60°C
Answer:
m = 0.0035 m.
Explanation:
Hello there!
In this case, since the formula for the computation of the molality is:
We can first compute the moles of solute, K3PO4 by using its molar mass:
Next, since the volume of water is 40.0 mL and its density is 1.00 g/mL we infer we have the same grams (40.0 g). Thus, we obtain the following molality by making sure we use the mass of water in kilograms (0.04000kg):
In molal units (m=mol/kg).
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