Moles of Oxygen they took in : C. 2.42
<h3>Further explanation</h3>
The gas equation can be written
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08205 l.atm / mol K
T = temperature, Kelvin
P=1000 kPa
V = 6 L
T = 298 K
moles of Oxygen :
Temperature, pressure ,weathering ,and erosion :)
The charges on a droplet can be used to represent the number of electrons carried by this droplet.
In other words:
a droplet having a charge of 1.60 x 10^-19 has 1.60 x 10^-19 electrons while a droplet having a charge of 3.15 x 10^-19 has <span>3.15 x 10^-19 electrons.
From the observations:
The fact that the droplets carried different charges signifies the fact the different droplets carried different numbers of electrons</span>
Answer:
Explanation:
T₁ = 100 + 273 = 373K
T₂ = 273 + 119 = 392 K
V₁ = initial volume
V₂ = Final volume
P₁ = P₁
P₂ = .85P₁
Using gas law equation
V₂ = 1.236 V₁
% increase in volume
= V₂-V₁ / V₁ x 100
= (1.236 V₁ - V₁ / V₁)x 100
= .236 x 100
= 23.6 % .
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