Answer:
6. 7870 kg/m³ (3 s.f.)
7. 33.4 g (3 s.f.)
8. 12600 kg/m³ (3 s.f.)
Explanation:
6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.
1 kg= 1000g
1m³= 1 ×10⁶ cm³
Mass of iron bar
= 64.2g
= 64.2 ÷1000 kg
= 0.0642 kg
Volume of iron bar
= 8.16 cm³
= 8.16 ÷ 10⁶
![= 8.16 \times 10^{ - 6} \: kg](https://tex.z-dn.net/?f=%20%3D%208.16%20%5Ctimes%2010%5E%7B%20-%206%7D%20%5C%3A%20%20kg)
![\boxed{density = \frac{mass}{volume} }](https://tex.z-dn.net/?f=%5Cboxed%7Bdensity%20%3D%20%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20%7D)
Density of iron bar
![= \frac{0.0642}{8.16 \times 10^{ - 6} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B0.0642%7D%7B8.16%20%5Ctimes%2010%5E%7B%20-%206%7D%20%7D%20)
= 7870 kg/m³ (3 s.f.)
7.
![\boxed{mass = density \: \times volume}](https://tex.z-dn.net/?f=%5Cboxed%7Bmass%20%3D%20density%20%5C%3A%20%20%5Ctimes%20volume%7D)
Mass
= 1.16 ×28.8
= 33.408 g
= 33.4 g (3 s.f.)
8. Volume of brick
= 12 cm³
![= 12 \times 10^{ - 6} \: m^{3} \\ = 1.2 \times 10^{ - 5} \: m ^{3}](https://tex.z-dn.net/?f=%20%3D%2012%20%20%5Ctimes%20%2010%5E%7B%20-%206%7D%20%20%5C%3A%20m%5E%7B3%7D%20%20%5C%5C%20%20%3D%201.2%20%5Ctimes%2010%5E%7B%20-%205%7D%20%20%5C%3A%20m%20%5E%7B3%7D%20)
Mass of brick
= 151 g
= 151 ÷ 1000 kg
= 0.151 kg
Density of brick
= mass ÷ volume
![= \frac{0.151} {1.25 \times 10^{ - 5} } \\ = 12600 \: kg/ {m}^{3}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B0.151%7D%20%7B1.25%20%5Ctimes%2010%5E%7B%20-%205%7D%20%7D%20%20%5C%5C%20%20%3D%2012600%20%5C%3A%20kg%2F%20%7Bm%7D%5E%7B3%7D%20)
(3 s.f.)
Answer:
None of these are correct, because there is no way to balance this equation, but I hope these steps help you figure out your answer.
Explanation:
Count out the single amounts of elements you have on both sides of the equation. To be balanced, you need to have the exact same for each element.
Before balanced Left side.
Cl-2
O-8
H-2
Before balanced right side.
H-1
Cl-1
O-3
That means we need to increase Hydrogen, Chlorine and Oxygen on the right for sure and see how that affects the equation. You can keep adding the Coefficients until the # of elements begin to match on each side.
(I tried to balance this equation, it doesn't work, there is too much on the reactants side for what the product is.)
Answer:
Spanish I dont know spanish.
Explanation:
Benzaldehyde or C6H5CHO would not undergo the aldol condensation because it does not contain an alpha-hydrogen in its structure. Aldol condensation is a type of reaction that happens between an enolate and an aldehyde or ketone leading to a alkene that has a planar structure. The lack of an alpha-hydrogen would not allow for it to undergo such process since it cannot enolize. Benzaldehyde undergoes a nucleophilic reaction known as Claisen-Schmidt condensation. It has somehow same mechanism of the aldol reaction however, the nucleophilic attack on the carbonyl happens even without the alpha-hydrogen but with an enolate that is from a ketone.