Independent- nose of the airplane
dependent - paper clips
control - how many paper clips
Answer:
The speed of the particle is 2.86 m/s
Explanation:
Given;
radius of the circular path, r = 2.0 m
tangential acceleration, = 4.4 m/s²
total magnitude of the acceleration, a = 6.0 m/s²
Total acceleration is the vector sum of tangential acceleration and radial acceleration
where;
is the radial acceleration
The radial acceleration relates to speed of particle in the following equations;
where;
v is the speed of the particle
Therefore, the speed of the particle is 2.86 m/s
Answer:
Explanation:
The acceleration of the motorcycle is given by
where
v=24 m/s is the final velocity of the motorcycle
u=15 m/s is the initial velocity
t=3 s is the time taken
Substituting these numbers into the equation, we find
Answer:
Vf = 4.40 m/s and θ = 88º
Explanation:
To solve this problem, let's look for the resultants of the force and with this we calculate the accelerations in each axis.
Let's use trigonometry to break down the forces
Sin 25 = F1x / F1
Cos 25 = F1y / F1
Fix = F1 sin 25
F1x = 1.85 sin 25
F1x = 0.78 N
F1y = 1.85 cos 25
F1y = 1.67 N
F2 = - 0.782 N j ^ (south)
F3 = - 0.750 N i ^ (west)
We write Newton's second law
X axis (East-West)
F1x - F3 = m ax
ax = (F1x - F3) / m
ax = (0.78 - (0.750)) / 0.325
ax = 0.092 m / s²
Y axis (North-South)
F1y - F2 = m ay
ay = (1.67- (0.782)) / 0.325
ay = 2.73 m / s²
Let's calculate the magnitude and direction of the acceleration
a = RA ax2 + ay2
a = RA 0.092² + 2.73²
a = 2.73m / s²
tan θ = ay / ax
θ = tan⁻¹ (2.73/0.092)
θ = tan⁻¹ 29.67
θ = 88º
We calculate the speed, notice that we use the total acceleration to be able to use the totol displacement
Vf² = vo² + 2 at D
Vf² = 0 + 2 2.73 3.55
Vf = √ 19.38
Vf = 4.40 m / s
θ = 88º
Answer:
1) Option D is correct.
The electric field inside a conductor is always zero.
2) Option A is correct.
The charge density inside the conductor is 0.
3) Charge density on the surface of the conductor at that point = η = -E ε₀
Explanation:
1) The electric field is zero inside a conductor. Any excess charge resides entirely on the surface or surfaces of a conductor.
Assuming the net electric field wasn't zero, current would flow inside the conductor and this would build up charges on the exterior of the conductor. These charges would oppose the field, ultimately (in a few nanoseconds for a metal) canceling the field to zero.
2) Since there are no charges inside a conductor (they all reside on the surface), it is logical that the charge density inside the conductor is also 0.
3) Surface Charge density = η = (q/A)
But electric field is given as
E = (-q/2πε₀r²)
q = -E (2πε₀r²)
η = (q/A) = -E (2πε₀r²)/A
For an elemental point on the surface,
A = 2πrl = 2πr²
So,
η = -E ε₀
Hope this Helps!!!