Answer:
The speed of the particle is 2.86 m/s
Explanation:
Given;
radius of the circular path, r = 2.0 m
tangential acceleration,
= 4.4 m/s²
total magnitude of the acceleration, a = 6.0 m/s²
Total acceleration is the vector sum of tangential acceleration and radial acceleration

where;
is the radial acceleration

The radial acceleration relates to speed of particle in the following equations;

where;
v is the speed of the particle

Therefore, the speed of the particle is 2.86 m/s