If ur meaning cavins. a cavin is like a cave or a hollow route. idk if thats what ur asking?
Boss tweed encourage his associates to work like a well oiled machine
thus providing his workers with benefits that encourages them to work like a
well oiled machine. A well oiled machine means that it does not stop, its work
is continuous and efficient.
Answer:
T² ∝ R³
Explanation:
Given data,
The period of revolution of the planet around the sun, T
The mean distance of the planet from the sun, R
According to the III law of Kepler, " Law of Periods' states that the square of the orbital period to go around the sun once is directly proportional to the cube of the mean distance between the sun and the planet.
T² ∝ R³
![\frac{T^{2}}{R^{3}} = Constant](https://tex.z-dn.net/?f=%5Cfrac%7BT%5E%7B2%7D%7D%7BR%5E%7B3%7D%7D%20%3D%20Constant)
From the above equation it is clear that T² varies directly as the R³.
Answer:
![F=27.39N](https://tex.z-dn.net/?f=F%3D27.39N)
Explanation:
Take sum of torques at the point the step touches the wheel, that eliminates two torques
Σ![T=T_{N}+T_{f}+T_{W}](https://tex.z-dn.net/?f=T%3DT_%7BN%7D%2BT_%7Bf%7D%2BT_%7BW%7D)
Since we are looking for when the wheel just starts to rise up N-> 0 so no torque due to normal force
![T_{N}=0](https://tex.z-dn.net/?f=T_%7BN%7D%3D0)
The perpendicular lever arm for the F force is R-h
![T_{f}=F*(r-h)](https://tex.z-dn.net/?f=T_%7Bf%7D%3DF%2A%28r-h%29)
And the T of gravity according to the image
![T_{W}=W*(\sqrt{r^2-(r-h)^2}](https://tex.z-dn.net/?f=T_%7BW%7D%3DW%2A%28%5Csqrt%7Br%5E2-%28r-h%29%5E2%7D)
Σ![T=0](https://tex.z-dn.net/?f=T%3D0)
![T_{N}+T_{f}+T_{W}=0](https://tex.z-dn.net/?f=T_%7BN%7D%2BT_%7Bf%7D%2BT_%7BW%7D%3D0)
![F*(r-h)+W*(\sqrt{r^2-(r-h)^2}=0](https://tex.z-dn.net/?f=F%2A%28r-h%29%2BW%2A%28%5Csqrt%7Br%5E2-%28r-h%29%5E2%7D%3D0)
![F=\frac{W*(\sqrt{r^2-(r-h)^2}}{r-h}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7BW%2A%28%5Csqrt%7Br%5E2-%28r-h%29%5E2%7D%7D%7Br-h%7D)
![F=\frac{24.9 N*(\sqrt{0.336^2-(0.336-0.110)^2}}{(0.336-0.11)}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B24.9%20N%2A%28%5Csqrt%7B0.336%5E2-%280.336-0.110%29%5E2%7D%7D%7B%280.336-0.11%29%7D)
![F=27.39N](https://tex.z-dn.net/?f=F%3D27.39N)
Given,
The initial inside diameter of the pipe, d₁=4.50 cm=0.045 m
The initial speed of the water, v₁=12.5 m/s
The diameter of the pipe at a later position, d₂=6.25 cm=0.065 m
From the continuity equation,
![\begin{gathered} A_1v_1=A_2v_2 \\ \pi(\frac{d_1}{2})^2v_1=\pi(\frac{d_2}{2})^2v_2 \\ \Rightarrow d^2_1v_1=d^2_2v_2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A_1v_1%3DA_2v_2%20%5C%5C%20%5Cpi%28%5Cfrac%7Bd_1%7D%7B2%7D%29%5E2v_1%3D%5Cpi%28%5Cfrac%7Bd_2%7D%7B2%7D%29%5E2v_2%20%5C%5C%20%5CRightarrow%20d%5E2_1v_1%3Dd%5E2_2v_2%20%5Cend%7Bgathered%7D)
Where A₁ is the area of the cross-section at the initial position, A₂ is the area of the cross-section of the pipe at a later position, and v₂ is the flow rate of the water at the later position.
On substituting the known values,
![\begin{gathered} 0.045^2\times12.5=0.065^2\times v_2 \\ \Rightarrow v_2=\frac{0.045^2\times12.5}{0.065^2} \\ =5.99\text{ m/s} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%200.045%5E2%5Ctimes12.5%3D0.065%5E2%5Ctimes%20v_2%20%5C%5C%20%5CRightarrow%20v_2%3D%5Cfrac%7B0.045%5E2%5Ctimes12.5%7D%7B0.065%5E2%7D%20%5C%5C%20%3D5.99%5Ctext%7B%20m%2Fs%7D%20%5Cend%7Bgathered%7D)
Thus, the flow rate of the water at the later position is 5.99 m/s