Answer: Rub the rod with a piece of metal that is already magnetized. Or
Rub the rod with two magnets, drawing the north pole of one magnet from the center of the rod to one end while you draw the south pole of the other magnet in the opposite direction.
Explanation:
It would be static friction which is what you have to overcome when an object is not in motion. When you move an object friction works against it like gravity and air resistance. I hope this helps!
Gradient of the line is m =-2/5
The work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
<h3>
Work done by a single force on the chandelier</h3>
The work done by a single force on the chandelier is determined by taking the net horizontal force applied on the chandelier over the given distance.
where;
is frictional force = 0 (smooth surface).
<h3>Work done by the two forces</h3>
When the two forces combine to pull the chandelier, the total work done will be shared by the two forces.
Thus, the work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
Learn more about work done here: brainly.com/question/8119756
Thats hard. i would have to say work the problem out