Answer:
The answer is C. How many 3/4 -pound molds are in 1/3 pound of sand?
Answer:
See below
Step-by-step explanation:
Vertical velocity will be affected by gravity in this scenario
df = do + vo t + 1/2 a t^2 do = original height = 4 ft a = -32.2 ft/s^2
<u>df = 4 + 89 t - 1/2 (32.2) t^2 df = height</u>
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On the way up and the way down, the ball may reach height of 102.2125 ft :
102.2125 = 4 + 89 t - 1/2 (32.2) t2 re-arrange to:
-16.1 t^2 + 89t - 98.2125 =0
Use Quadratic Formula to find <u>t = 1.5 and 4.0 s </u>
y = Acos(Bx) + D;
D = 4, A = 2. Now T = 2π/B = 5π/8, B = 2π/(5π/8) = 16/5
WE get y = 2cos(16/5x) + 4
Answer:
-1, 3, 3, -3
Step-by-step explanation:
On Edg
