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3 years ago

4. A force of 5 N gives a mass m,, an acceleration of 10 m's, and a mass

Physics

1 answer:

Art [367]3 years ago

8 0

Answer:

For mass m 1 newton 2nd law

F=m 1 a 1

5=m 1 ×10

m 1 = 2 1 kg

For mass m 2

F=m 2 a 2

5=m 2 ×20

m 2 = 4 1 kg

if tied together

Total mass =m 1 +m 2 = 1/2 +1/4=3/4kg

Now

F=M T Q T

a T = 5/m T = 5×4/3 = 3 /20m/s^2

Explanation:

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2 years ago

A pencil rolls horizontally of a 1 meter high desk and lands .25 meters from the base of the desk. How fast was the pencil rolli

vovikov84 [41]

Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

$x=V_{o} cos\theta t$ (1)

$y=y_{o}+Vo sin \theta t + \frac{g}{2}t^{2}$ (2)

Where:

$x=0.25 m$ is the horizontal displacement of the pencil

$V_{o}$ is the pencil's initial velocity

$\theta=0\°$ since we are told the pencil rolls <u>horizontally</u> before falling

$t$ is the time since the pencil falls until it hits the ground

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$y=0$ is the final height of the pencil (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity, always acting vertically downwards

Begining with (1):

$x=V_{o} cos(0\°) t$ (3)

$x=V_{o}t$ (4)

Finding $t$ from (2):

$0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2}$ (5)

$t=\sqrt{\frac{-2y_{o}}{g}}$ (6)

Substituting (6) in (4):

$x=V_{o}\sqrt{\frac{-2y_{o}}{g}}$ (7)

Isolating $V_{o}$ :

$V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}}$ (8)

$V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}}$ (9)

Finally:

$V_{o}=0.55 m/s$

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4 years ago

A ramp is used to lift a refrigerator a height of 12 m with a force of 110 N. The ramp is at an angle of 50° to the ground.How m

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Answer:

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Explanation:

We are given that

Height,h=12 m

Force,F=110 N

$\theta=50^{\circ}$

We have to find the work done .

We know that

Work done,W= $Fscos\theta$

Using the formula

W= $110\times 12cos50$

W=848.5 J

Hence,the work done=848.5 J

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