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Either B. or C. I am pretty sure it is B.
Answer:
2.5 mi/s^2
Explanation:
please see paper for work!
Answer:
Part a)
T = 0.52 s
Part b)

Part c)

Explanation:
As we know that the particle move from its maximum displacement to its mean position in t = 0.13 s
so total time period of the particle is given as

now we have
Part a)
T = time to complete one oscillation
so here it will move to and fro for one complete oscillation
so T = 0.52 s
Part b)
As we know that frequency and time period related to each other as



Part c)
As we know that
wavelength = 1.9 m
frequency = 1.92 Hz
so wave speed is given as



You have to use the specific heat equation.
Q = cmΔT where Q is the energy, c is specific heat, m is mass, and ΔT is change in temp.
So we can substitute our variables into the equation.
30000J = (390g)(3.9J*g/C)ΔT
Solving for ΔT, we get:
30000J/[(390g)*(3.9J*g/C) = ΔT
ΔT = 19.72386588C
I'm assuming the temperature is C, since it was not specified.
Hope this helps!