So to find the value of -3 do the following process:
Insert the -3 in the x’s in the equation on the top of the table
y= 5x -3x to the second power + 3
y= 5 (-3) -3(-3) to the second power + 3
Then continue to simplify the equation
y= -15 + 9 to the second power + 3
y= -15 + 84
y = 69
Y= 69 for the chart for -3
For b, c, and d insert the number in the x values and simplify like the previous equation.
If you are confused, feel free to ask questions. I hope this is effective and helps you in your studies.
Answer:
-2q - 6
Step-by-step explanation:
Step 1: Rewrite expression
-6 + 4q - 6q
Step 2: Combine like terms
-6 - 2q
Step 3: Rearrange
-2q - 6
Answer:
Pair 1: 9 and 3 Pair 2: 3 and 9
Step-by-step explanation:
The difference is 6 and one three times more than the other. Draw a diagram below:
Figure out 1 unit: 6÷2=3
3 = one unit
3 is the first number
Figure out second number: 3+6=9
3 & 9, 9 & 3
So, Pair 1: 9 and 3 Pair 2: 3 and 9
20/35 and 21/35. The common denominator is 35.
Where the function f is discontinuous and continuous is mathematically given as
- f(x) is not continuous at x = 0.
- f(x) is left continuous at x = 1
- f(x) is right continuous for all x =5
<h3>What
are the numbers at which f is discontinuous or continuous?</h3>
Generally, the equation for is mathematically given as
Since x+1, 1/x, and (x-5), the function does not "break" since these three terms are continuous. at
According to the dictionary definition of continuity, the function f(x) is continuous at x = a if:
lim (x->a-) f(x) = lim (x->a+) f(x) = f(a).
for x = 0
lim (x->0-) f(x)
= lim (x->0-) (x+1),
since f(x) = x+1 for 
f(x<=1) = 1 + 0
f(x<=1)= 1
lim (x->0+) f(x)= lim (x-->0+) ( √(x-5) ), since f(x)
lim (x->0+) f(x)= √(x-5 for x>=5
lim (x->0+) f(x)= 5
In conclusion,
- f(x) is not continuous at x = 0.
- f(x) is left continuous at x = 1
- f(x) is right continuous for all x =5
Read more about discontinuous
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Complete Question
Find the numbers at which f is discontinuous. Then determine whether f is continuous from the right, from the left, or neither at each point of discontinuity.
f(x)={ x+1 if x< 1
1/x if 1<x<5
√(x-5) if x> 5