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kirill [66]
3 years ago
9

Can someone help me with this one

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0
X = 21 + 34
Answer: x = 55°
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2 bags of cement cost 3500 how many bags can one buy with 17500​
timofeeve [1]

Answer:

10

Step-by-step explanation:

2 → $3500

? → $17500

? = 17500 x 2 / 3500 = 3500/3500 = 10

OR

3500 → 2

3500/2 = 1750

17500/1750 = 10

Therefore, whatever method you use, you will get 10 as an answer.

4 0
3 years ago
Read 2 more answers
At an electronics store, the number of 37 inch HDTVs that is expected to be sold in a month is double that of 58 inch HDTVs and
ki77a [65]
Will represent as such
number of 37 inch tvs=x
number of 58 inch tvs=y
number of 50 inch tvs =z

x is double of (y+z)
x=2(y+z)
y=z
therefor
x=2(y+y)=2(z+z)=4y=4z
x=4y=4z
y=$4800
z=$2000
x=$1800


4800y+2000z+1800x=168000
undistribute the 100
100(48y+20z+18x)=100(1680)
divide the whole thing by 100
48y+20z+18x=1680
divide the whole thing by 2
24y+10z+9x=840
y=z
24y+10z=34y or 34z
34y+9x=840
convert 9x to y by multiply 4
9x times 4=36y or 36z
34y+36y=840
70y=840
divide both sides by 70
y=12
y=z
z=12
x=4z
x=4(12)
x=48






they should stock:
12      50 inch tvs
12      58 inch tvs
48      38 inch tvs
3 0
4 years ago
A sequence of transformations that maps △RST to △R′S′T′ is a
blondinia [14]
Hey I'm on this question on my test too. I think the answer is:

First Box: "Reflection across the x-axis" 
Last Box: "Translation 1 unit down"

What the sentence should look like =  "<span>△RST</span><span> to </span><span>△<span>R′</span><span>S′</span><span>T′</span></span><span> is a reflection across the x-axis followed by a translation 1 unit down."

I hope this helps!</span>

6 0
4 years ago
A survey conducted in July 2015 asked a random sample of American adults whether they had ever used online dating (either an onl
Natasha2012 [34]

Answer:

The 99% confidence interval is (0.0787, 0.1613).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

The survey included 411 adults between the ages of 55 and 64, and 50 of them said that they had used online dating. This means that n = 411, \pi = \frac{50}{411} = 0.12

The 99% confidence interval is

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{411}} = 0.12 - 2.575\sqrt{\frac{0.12*0.88}{411}} = 0.0787

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{411}} = 0.12 + 2.575\sqrt{\frac{0.12*0.88}{411}} = 0.1613

The 99% confidence interval is (0.0787, 0.1613).

3 0
4 years ago
Simplify. 7 2/3+ -5 1/4<br><br>A. -2<br><br>B. 2 5/12<br><br>C. 2 11/12<br><br>D. 12 11/12​
sergij07 [2.7K]

Answer:

B.

Step-by-step explanation:

6 0
3 years ago
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