Answer:
a) Percentage of students scored below 300 is 1.79%.
b) Score puts someone in the 90th percentile is 638.
Step-by-step explanation:
Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.
(a) If the average test score is 510 with a standard deviation of 100 points.
To find : What percentage of students scored below 300 ?
Solution :
Mean 
,
Standard deviation 
Sample mean 
Percentage of students scored below 300 is given by,
Percentage of students scored below 300 is 1.79%.
(b) What score puts someone in the 90th percentile?
90th percentile is such that,
Now, 
Score puts someone in the 90th percentile is 638.
B. 10 and 11
This is because 10x10 is 100, so thats less than what you need and then 11x11 is 121, and that is more than you need... So it would be between 10 and 11.
Answer:
y=x+3
Step-by-step explanation:
1.) Find slope
slope = (-1-3)/(-4-0)
= -4/-4
= 1
2.) Use point slope form
<u>y-y1= m (x-x1) </u>
both x1 and y1 are the points
m is the slope
3.) Plug in the numbers
for the points I chose (0,3) to plug in
y-3= 1 (x1-0)
y-3= x
y= x+3
Answer:
4.24 km
Step-by-step explanation:
The x-component of the displacement after the turn is ...
d2·cos(θ) = (3.38 km)cos(65.3°) ≈ 1.41239 km
Adding this to the displacement before the turn, we have ...
x-component of displacement = 2.83 km + 1.41 km = 4.24 km
✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧
Hello!
✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧
❖ The volume of the container is 52 units.
4*4*4 = 64
64 - 8 = 52
~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡
~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ
